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A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?
- a)Treatment with Pd/CaCO3/H2 would make it achiral
- b)Treatment with Na/NH3 (l) would make it achiral
- c)Treatment with Raney nickel-H2 would make it achiral
- d)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketones
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A chiral hydrocarbon has molar mass 82 and it gives effervescence when...
A chiral hydrocarbon -Na → H2
There is terminal triple bond in the reactant hydrocarbon because,
R - C ≡ C - H -NaR - C ≡ O Na++H2
Molecular mass = 82i.e., It is C6H10
(a) CH3 - CH2 - CH - C ≡ CH
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CH3
H2 | Pd | CaCO3
CH3 - CH2 - *CH - CH = CH2
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CH3
Option A is wrong as it is chiral
CH3 - CH2 - CH - C ≡ CH
|
CH3
Na| NH3
CH3 - CH2 - *CH - CH = CH2
|
CH3
Option B is wrong as it is chiral
CH3 - CH2 - CH - C ≡ CH
|
CH3
H2 | Ni
CH3 - CH2 - CH - CH2 = CH2
|
CH3
Option C is correct as it is achiral
There is terminal triple bond in the reactant hydrocarbon because,
R - C ≡ C - H -NaR - C ≡ O Na++H2
Molecular mass = 82i.e., It is C6H10
(a) CH3 - CH2 - CH - C ≡ CH
|
CH3
H2 | Pd | CaCO3
CH3 - CH2 - *CH - CH = CH2
|
CH3
Option A is wrong as it is chiral
CH3 - CH2 - CH - C ≡ CH
|
CH3
Na| NH3
CH3 - CH2 - *CH - CH = CH2
|
CH3
Option B is wrong as it is chiral
CH3 - CH2 - CH - C ≡ CH
|
CH3
H2 | Ni
CH3 - CH2 - CH - CH2 = CH2
|
CH3
Option C is correct as it is achiral
Most Upvoted Answer
A chiral hydrocarbon has molar mass 82 and it gives effervescence when...
Chirality of the Hydrocarbon
- The fact that the hydrocarbon is chiral indicates that it has a non-superimposable mirror image, making it optically active.
Treatment with Raney Nickel-H2
- Raney Nickel is a catalyst commonly used for hydrogenation reactions. When the chiral hydrocarbon is treated with Raney Nickel in the presence of hydrogen gas (H2), it undergoes a hydrogenation reaction.
- The hydrogenation reaction reduces the double bonds or functional groups present in the hydrocarbon, leading to the formation of a saturated compound.
- In this process, the chiral centers in the hydrocarbon are altered or removed, resulting in the formation of an achiral compound.
- Therefore, treatment with Raney Nickel-H2 would indeed make the original chiral hydrocarbon achiral.
Other Treatment Options
- Treatment with Pd/CaCO3/H2 or Na/NH3 (l) may not necessarily result in the conversion of the chiral hydrocarbon to an achiral compound.
- Its reaction with HgSO4/H2SO4(aq) to give a mixture of ketones is not directly related to the chirality of the hydrocarbon.
In conclusion, the correct statement is option 'C' as treatment with Raney Nickel-H2 would effectively make the original chiral hydrocarbon achiral.
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A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer?.
A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer?.
Solutions for A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A chiral hydrocarbon has molar mass 82 and it gives effervescence when heated with Na metal. What is true about the original hydrocarbon?a)Treatment with Pd/CaCO3/H2 would make it achiralb)Treatment with Na/NH3 (l) would make it achiralc)Treatment with Raney nickel-H2 would make it achirald)It’s reaction with HgSO4/ H2SO4(aq) gives a mixture of ketonesCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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