Which branched chain isomer of the hydrocarbon with molecular mass 72u...
Explanation:
The molecular mass of the hydrocarbon is given as 72u. To determine the branched chain isomer that gives only one isomer of mono substituted alkyl halide, we need to consider the different possibilities for the hydrocarbon.
1. Neopentane (option A):
- The formula of neopentane is C5H12.
- In neopentane, all the carbon atoms are connected in a branched chain.
- Since there are no methyl groups attached to the carbon atoms, there is only one possible position for substitution with an alkyl halide.
- Therefore, neopentane gives only one isomer of mono substituted alkyl halide.
2. Isohexane (option B):
- The formula of isohexane is C6H14.
- In isohexane, the carbon atoms are connected in a branched chain.
- However, there are two possible positions for substitution with an alkyl halide, as there are two methyl groups attached to the carbon atoms.
- Therefore, isohexane does not give only one isomer of mono substituted alkyl halide.
3. Neohexane (option C):
- The formula of neohexane is C6H14.
- In neohexane, the carbon atoms are connected in a branched chain.
- There are three possible positions for substitution with an alkyl halide, as there are three methyl groups attached to the carbon atoms.
- Therefore, neohexane does not give only one isomer of mono substituted alkyl halide.
4. Tertiary butyl chloride (option D):
- The formula of tertiary butyl chloride is C4H9Cl.
- Tertiary butyl chloride is not a branched chain hydrocarbon but a substituted alkyl halide.
- It does not meet the criteria for the given question, as it is not a branched chain hydrocarbon.
Therefore, the correct answer is option A, neopentane, as it is the only branched chain isomer of the hydrocarbon with molecular mass 72u that gives only one isomer of mono substituted alkyl halide.
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