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A piece of thin wire in the form of an equilateral triangle of side 8.8 dm is bent into a circle with no loss in wire. Find the diameter of the circle?
Most Upvoted Answer
A piece of thin wire in the form of an equilateral triangle of side 8....

Solution:

Given:
- Side of equilateral triangle = 8.8 dm

Calculating the perimeter of the equilateral triangle:
- Perimeter of an equilateral triangle = 3 * side
- Perimeter = 3 * 8.8 dm
- Perimeter = 26.4 dm

Using the perimeter to find the circumference of the circle:
- The wire is bent into a circle, so the perimeter of the triangle is equal to the circumference of the circle.
- Circumference of a circle = 2 * π * radius
- 26.4 dm = 2 * π * radius
- Radius = 26.4 dm / (2 * π) = 4.2 dm

Calculating the diameter of the circle:
- Diameter = 2 * radius
- Diameter = 2 * 4.2 dm
- Diameter = 8.4 dm

Therefore, the diameter of the circle formed by bending the wire into an equilateral triangle is 8.4 dm.
Community Answer
A piece of thin wire in the form of an equilateral triangle of side 8....
84cm is the diameter
42cm is the radius
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A piece of thin wire in the form of an equilateral triangle of side 8.8 dm is bent into a circle with no loss in wire. Find the diameter of the circle?
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A piece of thin wire in the form of an equilateral triangle of side 8.8 dm is bent into a circle with no loss in wire. Find the diameter of the circle? for Class 7 2024 is part of Class 7 preparation. The Question and answers have been prepared according to the Class 7 exam syllabus. Information about A piece of thin wire in the form of an equilateral triangle of side 8.8 dm is bent into a circle with no loss in wire. Find the diameter of the circle? covers all topics & solutions for Class 7 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A piece of thin wire in the form of an equilateral triangle of side 8.8 dm is bent into a circle with no loss in wire. Find the diameter of the circle?.
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