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Aluminium-25 decay by emitting a positron. The species immediately produced has:
- a)12p, 13n, 13e–
- b)13p, 12n, 13e–
- c)12p, 13n, 12e–
- d)14p, 11n, 14e–
Correct answer is option 'C'. Can you explain this answer?
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B)12p, 12n, 13e
The correct answer is b) 12p, 12n, 13e.
When Aluminium-25 (25Al) decays by emitting a positron (β+), it undergoes beta plus decay, which converts a proton into a neutron while emitting a positron and a neutrino. The resulting nucleus has one less proton and one more neutron than before, but the same mass number. Therefore, the product of the decay is a new element with the same mass number but one less atomic number.
The equation for the decay of 25Al is:
25Al → 24Mg + β+ + νe
This means that 25Al (which has 13 protons and 12 neutrons) decays into 24Mg (which has 12 protons and 12 neutrons), a positron (e+) and a neutrino (νe).
The positron is a positively charged electron, which is immediately annihilated when it encounters an electron with the opposite charge. This produces two gamma rays (γ) with energy of 0.511 MeV each.
Therefore, the species immediately produced by the decay of 25Al is 24Mg with 12 protons, 12 neutrons, and 13 electrons.
The correct answer is b) 12p, 12n, 13e.
When Aluminium-25 (25Al) decays by emitting a positron (β+), it undergoes beta plus decay, which converts a proton into a neutron while emitting a positron and a neutrino. The resulting nucleus has one less proton and one more neutron than before, but the same mass number. Therefore, the product of the decay is a new element with the same mass number but one less atomic number.
The equation for the decay of 25Al is:
25Al → 24Mg + β+ + νe
This means that 25Al (which has 13 protons and 12 neutrons) decays into 24Mg (which has 12 protons and 12 neutrons), a positron (e+) and a neutrino (νe).
The positron is a positively charged electron, which is immediately annihilated when it encounters an electron with the opposite charge. This produces two gamma rays (γ) with energy of 0.511 MeV each.
Therefore, the species immediately produced by the decay of 25Al is 24Mg with 12 protons, 12 neutrons, and 13 electrons.
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Aluminium-25 decay by emitting a positron. The species immediately produced has:a)12p, 13n, 13e–b)13p, 12n, 13e–c)12p, 13n, 12e–d)14p, 11n, 14e–Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Aluminium-25 decay by emitting a positron. The species immediately produced has:a)12p, 13n, 13e–b)13p, 12n, 13e–c)12p, 13n, 12e–d)14p, 11n, 14e–Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Aluminium-25 decay by emitting a positron. The species immediately produced has:a)12p, 13n, 13e–b)13p, 12n, 13e–c)12p, 13n, 12e–d)14p, 11n, 14e–Correct answer is option 'C'. Can you explain this answer?.
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