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If the pressure P(system) is greater than the P(surroundings), then:
- a)Work is done on the system by the surroundings.
- b)Work is done on the surroundings by the system.
- c)Work done on the system by the surroundings is equal to the work done on the surroundings by the system.
- d)Internal energy of the system increases.
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
If the pressure P(system) is greater than the P(surroundings), then:a)...
Explanation:
When the pressure of the system is greater than the pressure of the surroundings, the system is said to be under compression. This causes the system to do work on the surroundings, and the surroundings to resist the compression by doing work on the system. Therefore, the correct answer is option 'B' - work is done on the surroundings by the system.
Further Explanation:
- Work Done by the System: When a system is compressed, it does work on the surroundings. This is because the system is pushing against the surroundings, causing them to move or deform in some way. The work done by the system can be calculated using the formula:
W = -PΔV
Where W is the work done, P is the pressure, and ΔV is the change in volume.
- Work Done on the System: When the surroundings resist the compression, they do work on the system. This work is equal in magnitude but opposite in sign to the work done by the system. Therefore, the work done on the system can be calculated as:
W = PΔV
- Internal Energy: The internal energy of the system is a measure of the energy contained within the system, including the kinetic and potential energy of its particles. When a system is compressed, its internal energy increases. This is because the particles within the system are closer together, and therefore have a higher potential energy.
Conclusion:
To sum up, when the pressure of the system is greater than the pressure of the surroundings, the system is under compression, and the system does work on the surroundings. The surroundings resist the compression by doing work on the system, resulting in an increase in the internal energy of the system. Therefore, the correct answer is option 'B' - work is done on the surroundings by the system.
When the pressure of the system is greater than the pressure of the surroundings, the system is said to be under compression. This causes the system to do work on the surroundings, and the surroundings to resist the compression by doing work on the system. Therefore, the correct answer is option 'B' - work is done on the surroundings by the system.
Further Explanation:
- Work Done by the System: When a system is compressed, it does work on the surroundings. This is because the system is pushing against the surroundings, causing them to move or deform in some way. The work done by the system can be calculated using the formula:
W = -PΔV
Where W is the work done, P is the pressure, and ΔV is the change in volume.
- Work Done on the System: When the surroundings resist the compression, they do work on the system. This work is equal in magnitude but opposite in sign to the work done by the system. Therefore, the work done on the system can be calculated as:
W = PΔV
- Internal Energy: The internal energy of the system is a measure of the energy contained within the system, including the kinetic and potential energy of its particles. When a system is compressed, its internal energy increases. This is because the particles within the system are closer together, and therefore have a higher potential energy.
Conclusion:
To sum up, when the pressure of the system is greater than the pressure of the surroundings, the system is under compression, and the system does work on the surroundings. The surroundings resist the compression by doing work on the system, resulting in an increase in the internal energy of the system. Therefore, the correct answer is option 'B' - work is done on the surroundings by the system.
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If the pressure P(system) is greater than the P(surroundings), then:a)...
If pressure of system is greater than the surrounding, it will undergo expansion and hence option b
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If the pressure P(system) is greater than the P(surroundings), then:a)Work is done on the system by the surroundings.b)Work is done on the surroundings by the system.c)Work done on the system by the surroundings is equal to the work done on the surroundings by the system.d)Internal energy of the system increases.Correct answer is option 'B'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about If the pressure P(system) is greater than the P(surroundings), then:a)Work is done on the system by the surroundings.b)Work is done on the surroundings by the system.c)Work done on the system by the surroundings is equal to the work done on the surroundings by the system.d)Internal energy of the system increases.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the pressure P(system) is greater than the P(surroundings), then:a)Work is done on the system by the surroundings.b)Work is done on the surroundings by the system.c)Work done on the system by the surroundings is equal to the work done on the surroundings by the system.d)Internal energy of the system increases.Correct answer is option 'B'. Can you explain this answer?.
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