Civil Engineering (CE) Exam > Civil Engineering (CE) Questions > If a hydraulic jump occurring in a rectangula...
Start Learning for Free
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?
Correct answer is '3.7-3.9'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such...
Concept:
Using the relation,
y1 = Pre-jump depth
y2 = Post-jump depth
F1 = Froude number before jump
F2 = Froude number after jump
Energy loss is given by:
Calculation:
y2 = 2.45 m
F2 = 0.333
y1 = 0.458 m
EL = 1.761 m
Most Upvoted Answer
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such...
< b="" />Given data:< />
Width of the rectangular channel (b) = 2.5 m
Depth after the hydraulic jump (y2) = 2.45 m
Discharge in the channel (Q) = 10 m^3/sec
< b="" />Hydraulic Jump:< />
A hydraulic jump occurs when a supercritical flow (high velocity, low depth) changes to a subcritical flow (low velocity, high depth). In this process, energy is lost due to the conversion of kinetic energy into potential energy and turbulence.
< b="" />Energy loss in the hydraulic jump:< />
The energy loss (EL) in the hydraulic jump can be calculated using the specific energy equation:
E = y + (V^2 / 2g) --> Equation 1
Where,
E = specific energy
y = depth of flow
V = velocity of flow
g = acceleration due to gravity
Before the jump, the specific energy (E1) can be calculated as:
E1 = y1 + (V1^2 / 2g) --> Equation 2
After the jump, the specific energy (E2) can be calculated as:
E2 = y2 + (V2^2 / 2g) --> Equation 3
Since the discharge (Q) remains constant, we can use the Continuity Equation to relate the velocities before and after the jump:
Q = b1 * V1 = b2 * V2 --> Equation 4
< b="" />Calculation:< />
We are given the width of the channel (2.5 m), discharge (10 m^3/sec), and the depth after the jump (2.45 m). We need to find the ratio of energy loss (EL) to the pre-jump depth (y1).
1. Find the pre-jump depth (y1) using the continuity equation:
Q = b1 * V1
10 = 2.5 * V1
V1 = 4 m/sec
2. Substitute the values of y1, V1, y2, and Q into equations 2 and 3:
E1 = y1 + (V1^2 / 2g)
E2 = y2 + (V2^2 / 2g)
3. Calculate the energy loss (EL) using the equation:
EL = E1 - E2
4. Calculate the ratio of energy loss (EL) to the pre-jump depth (y1):
Ratio = EL / y1
< b="" />Final Result:< />
The ratio of energy loss (EL) in the hydraulic jump to the pre-jump depth (y1) is approximately 3.7 to 3.9.
Width of the rectangular channel (b) = 2.5 m
Depth after the hydraulic jump (y2) = 2.45 m
Discharge in the channel (Q) = 10 m^3/sec
< b="" />Hydraulic Jump:< />
A hydraulic jump occurs when a supercritical flow (high velocity, low depth) changes to a subcritical flow (low velocity, high depth). In this process, energy is lost due to the conversion of kinetic energy into potential energy and turbulence.
< b="" />Energy loss in the hydraulic jump:< />
The energy loss (EL) in the hydraulic jump can be calculated using the specific energy equation:
E = y + (V^2 / 2g) --> Equation 1
Where,
E = specific energy
y = depth of flow
V = velocity of flow
g = acceleration due to gravity
Before the jump, the specific energy (E1) can be calculated as:
E1 = y1 + (V1^2 / 2g) --> Equation 2
After the jump, the specific energy (E2) can be calculated as:
E2 = y2 + (V2^2 / 2g) --> Equation 3
Since the discharge (Q) remains constant, we can use the Continuity Equation to relate the velocities before and after the jump:
Q = b1 * V1 = b2 * V2 --> Equation 4
< b="" />Calculation:< />
We are given the width of the channel (2.5 m), discharge (10 m^3/sec), and the depth after the jump (2.45 m). We need to find the ratio of energy loss (EL) to the pre-jump depth (y1).
1. Find the pre-jump depth (y1) using the continuity equation:
Q = b1 * V1
10 = 2.5 * V1
V1 = 4 m/sec
2. Substitute the values of y1, V1, y2, and Q into equations 2 and 3:
E1 = y1 + (V1^2 / 2g)
E2 = y2 + (V2^2 / 2g)
3. Calculate the energy loss (EL) using the equation:
EL = E1 - E2
4. Calculate the ratio of energy loss (EL) to the pre-jump depth (y1):
Ratio = EL / y1
< b="" />Final Result:< />
The ratio of energy loss (EL) in the hydraulic jump to the pre-jump depth (y1) is approximately 3.7 to 3.9.
Attention Civil Engineering (CE) Students!
To make sure you are not studying endlessly, EduRev has designed Civil Engineering (CE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Civil Engineering (CE).
|
Explore Courses for Civil Engineering (CE) exam
|
|
Similar Civil Engineering (CE) Doubts
Top Courses for Civil Engineering (CE)View all
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer?
Question Description
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer?.
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer?.
Solutions for If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? in English & in Hindi are available as part of our courses for Civil Engineering (CE).
Download more important topics, notes, lectures and mock test series for Civil Engineering (CE) Exam by signing up for free.
Here you can find the meaning of If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer?, a detailed solution for If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? has been provided alongside types of If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice If a hydraulic jump occurring in a rectangular channel 2.5 m wide such that the depth after the jump is 2.45m. If the discharge in the rectangular channel is 10 m3/sec, then the ratio of energy loss (EL) in the jump to the pre-jump depth will be?Correct answer is '3.7-3.9'. Can you explain this answer? tests, examples and also practice Civil Engineering (CE) tests.
|
|
Explore Courses for Civil Engineering (CE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup