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The Rh—Rh bond order in [Rh(CO)(CS) (μ-Br)]2 is:
    Correct answer is '2'. Can you explain this answer?
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    The Rh—Rh bond order in [Rh(CO)(CS) (μ-Br)]2 is:Correct answe...
    (By Neutral method)
    Total valence electrons= 2*[ 9(for Rh)+2(for CO)+2(for CS) +3(For bridged Br) ] = 32
    Since there are 2 metals so following 18e rule for each....Total electron should be = 2*18=36
    Electrona remaining= 36-32 =4
    So metal bonds needed = 4/2 = 2
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    The Rh—Rh bond order in [Rh(CO)(CS) (μ-Br)]2 is:Correct answe...
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    The Rh—Rh bond order in [Rh(CO)(CS) (μ-Br)]2 is:Correct answer is '2'. Can you explain this answer?
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