The Rh—Rh bond order in [Rh(CO)(CS) (μ-Br)]2 is:Correct answe...
(By Neutral method)
Total valence electrons= 2*[ 9(for Rh)+2(for CO)+2(for CS) +3(For bridged Br) ] = 32
Since there are 2 metals so following 18e rule for each....Total electron should be = 2*18=36
Electrona remaining= 36-32 =4
So metal bonds needed = 4/2 = 2
The Rh—Rh bond order in [Rh(CO)(CS) (μ-Br)]2 is:Correct answe...
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