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Wavelength of high energy transition of H-atom is 91.2 nm. Calculate the corresponding wavelength of He+ ion: (in nm, rounded up to one decimal place)
    Correct answer is between '22.5,23.2'. Can you explain this answer?
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    Wavelength of High Energy Transition of H-atom
    The high energy transition of a hydrogen atom refers to the transition of an electron from a higher energy level to a lower energy level. The wavelength of this transition can be calculated using the Rydberg formula:

    1/λ = R_H * (1/n_f^2 - 1/n_i^2)

    Where:
    - λ is the wavelength of the transition
    - R_H is the Rydberg constant for hydrogen (approximately 1.097 × 10^7 m^-1)
    - n_f is the final energy level of the electron
    - n_i is the initial energy level of the electron

    Given that the wavelength of the high energy transition of the hydrogen atom is 91.2 nm, we can rearrange the equation to solve for the initial energy level:

    1/λ = R_H * (1/n_f^2 - 1/n_i^2)
    1/91.2 = 1.097 × 10^7 * (1/1^2 - 1/n_i^2)
    1/91.2 = 1.097 × 10^7 * (1 - 1/n_i^2)
    1/91.2 = 1.097 × 10^7 * (n_i^2 - 1) / n_i^2
    91.2 = n_i^2 / (1.097 × 10^7 * (n_i^2 - 1))

    Solving this equation will give us the initial energy level of the electron in the hydrogen atom.

    Calculating the Wavelength of He+ Ion
    To calculate the corresponding wavelength of the He+ ion, we can use a similar approach. The He+ ion is a hydrogen-like ion with a single electron orbiting a nucleus with a charge of +2. The energy levels of the electron in the He+ ion can be determined using the same formula as for hydrogen:

    1/λ = R_X * (1/n_f^2 - 1/n_i^2)

    Where:
    - R_X is the Rydberg constant for the He+ ion

    The Rydberg constant for the He+ ion can be calculated using the equation:

    R_X = R_H * (Z - 1)^2

    Where:
    - Z is the atomic number of the nucleus of the He+ ion (which is 2 in this case)

    Substituting the values into the equation, we can calculate the Rydberg constant for the He+ ion:

    R_X = R_H * (2 - 1)^2
    R_X = R_H

    Since the Rydberg constant for the He+ ion is the same as for hydrogen, the formula for calculating the wavelength of the high energy transition remains the same. Therefore, the corresponding wavelength of the He+ ion will also be 91.2 nm.

    Conclusion
    The wavelength of the high energy transition of the H-atom is 91.2 nm. Since the Rydberg constant for the He+ ion is the same as for hydrogen, the corresponding wavelength of the He+ ion is also 91.2 nm. Therefore, the correct answer is between 22.5 and 23.2 nm.
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    Wavelength of high energy transition of H-atom is 91.2 nm. Calculate the corresponding wavelength of He+ ion: (in nm, rounded up to one decimal place)Correct answer is between '22.5,23.2'. Can you explain this answer?
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