A gas cylinder containing cooking gas can withstand a pressure of 15 a...
°C. What is the actual pressure of the gas in the cylinder?
We can use the ideal gas law to solve this problem:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin:
T = 27 + 273.15 = 300.15 K
Next, we can rearrange the ideal gas law to solve for the actual pressure of the gas:
P = nRT/V
We know that the cylinder can withstand a pressure of 15 atm, and the pressure gauge indicates 10 atm. This means that the difference between the actual pressure and the gauge pressure is:
ΔP = 15 atm - 10 atm = 5 atm
So the actual pressure is:
P = 10 atm + 5 atm = 15 atm
Now we can use the ideal gas law to find the number of moles of gas:
n = PV/RT
We know the pressure, volume, and temperature, but we need to convert the volume from liters to cubic meters:
V = 0.01 m³
Putting in the values, we get:
n = (15 atm)(0.01 m³)/(0.0821 L·atm/mol·K)(300.15 K) = 0.00606 mol
Therefore, the actual pressure of the gas in the cylinder is 15 atm, and there are 0.00606 moles of gas in the cylinder.
A gas cylinder containing cooking gas can withstand a pressure of 15 a...
Pv = nRT... here volume of cylinder is constant ...so p = kT ..or, P1/T1 = P2/T2. . or, 10/300=15/T2...or T2 = 450