Time taken by a particle performing shm on astraight line to pass from A to B where itsvelocities are same is 2 sec. after 2 sec. it returns to b time period will be?

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Time taken by a particle performing shm on astraight line to pass from A to B where itsvelocities are same is 2 sec. after 2 sec. it returns to b time period will be
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Time taken by a particle performing shm on astraight line to pass from...

According to the question, a and b points are such that they are located at same distances from the equilibrium position. Here also it is said that velocity is same ,i.e; not only the magnitude but also the directions are same. So, total time period of oscillation = 2x( time taken to go from a to b + the next time taken to return at b) = 2x(2+2)= 8 sec

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Time taken by a particle performing shm on astraight line to pass from A to B where itsvelocities are same is 2 sec. after 2 sec. it returns to b time period will be?

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