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ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60° then ∠CDB = .............
  • a)
    60°
  • b)
    75°
  • c)
    45°
  • d)
    135°
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60&...
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Since ABCD is a parallelogram
then,
∠DAB=∠BCD=75°

Now, In ∆BCD

∠DBC=60°(Given)
∠BCD=75° (Proved above)
∠CDB=?

Here,

[From angle sum property of ∆]
∠DBC+∠BCD+∠CDB=180°
60°+75°+∠CDB= 180°
∠CDB = 180°-(60°+75°)
∠CDB = 180°-135°

📎∠CDB = 45°




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ABCD is a parallelogram in which ∠DAB = 75° and ∠DBC = 60° then ∠CDB = .............a)60°b)75°c)45°d)135°Correct answer is option 'C'. Can you explain this answer?
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