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133/R2= (1 £150)/(1 £500).where R2 is resistance at temperature 500C and R1 is 133 and £is temperature coefficient of resistance with value0.0045`c. Plz tell me how to solve this mathematically .i m a bio student;)?
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133/R2= (1 £150)/(1 £500).where R2 is resistance at temperature 500C and R1 is 133 and £is temperature coefficient of resistance with value0.0045`c. Plz tell me how to solve this mathematically .i m a bio student;)?
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133/R2= (1 £150)/(1 £500).where R2 is resistance at temperature 500C and R1 is 133 and £is temperature coefficient of resistance with value0.0045`c. Plz tell me how to solve this mathematically .i m a bio student;)? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about 133/R2= (1 £150)/(1 £500).where R2 is resistance at temperature 500C and R1 is 133 and £is temperature coefficient of resistance with value0.0045`c. Plz tell me how to solve this mathematically .i m a bio student;)? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 133/R2= (1 £150)/(1 £500).where R2 is resistance at temperature 500C and R1 is 133 and £is temperature coefficient of resistance with value0.0045`c. Plz tell me how to solve this mathematically .i m a bio student;)?.
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