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Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):
Correct answer is between '14.5,15.5'. Can you explain this answer?
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Consider an isothermal reversible compression of one mole of an ideal ...
Given data:
- Number of moles of gas (n) = 1
- Initial pressure (P1) = 5 atm
- Final pressure (P2) = 30 atm
- Temperature (T) = 300 K
Assumptions:
- The compression is isothermal and reversible, meaning the temperature remains constant during the process.
- The gas is ideal, which means it follows the ideal gas law.
Entropy change of the system:
Since the compression is isothermal and reversible, the entropy change of the system (ΔSsys) can be calculated using the equation:
ΔSsys = nR ln(P2/P1)
where R is the gas constant.
Using the given values, we can calculate the entropy change of the system:
ΔSsys = (1 mol)(8.314 J/mol·K) ln(30 atm/5 atm)
= (8.314 J/mol·K) ln(6)
≈ 14.5 J/K
Entropy change of the surroundings:
According to the second law of thermodynamics, the total entropy change of the universe is always greater than or equal to zero. In this case, since the system is undergoing a reversible process, the total entropy change of the universe (ΔSuniv) is zero. Therefore, the entropy change of the surroundings (ΔSsurr) is equal in magnitude but opposite in sign to the entropy change of the system.
ΔSuniv = ΔSsys + ΔSsurr
0 = 14.5 J/K + ΔSsurr
ΔSsurr = -14.5 J/K
Rounding and final answer:
The given answer range is between 14.5 and 15.5 J/K. Since ΔSsurr is -14.5 J/K, we can round it up to the nearest decimal place, which is 15 J/K. Therefore, the correct answer is between 14.5 and 15.5 J/K.
- Number of moles of gas (n) = 1
- Initial pressure (P1) = 5 atm
- Final pressure (P2) = 30 atm
- Temperature (T) = 300 K
Assumptions:
- The compression is isothermal and reversible, meaning the temperature remains constant during the process.
- The gas is ideal, which means it follows the ideal gas law.
Entropy change of the system:
Since the compression is isothermal and reversible, the entropy change of the system (ΔSsys) can be calculated using the equation:
ΔSsys = nR ln(P2/P1)
where R is the gas constant.
Using the given values, we can calculate the entropy change of the system:
ΔSsys = (1 mol)(8.314 J/mol·K) ln(30 atm/5 atm)
= (8.314 J/mol·K) ln(6)
≈ 14.5 J/K
Entropy change of the surroundings:
According to the second law of thermodynamics, the total entropy change of the universe is always greater than or equal to zero. In this case, since the system is undergoing a reversible process, the total entropy change of the universe (ΔSuniv) is zero. Therefore, the entropy change of the surroundings (ΔSsurr) is equal in magnitude but opposite in sign to the entropy change of the system.
ΔSuniv = ΔSsys + ΔSsurr
0 = 14.5 J/K + ΔSsurr
ΔSsurr = -14.5 J/K
Rounding and final answer:
The given answer range is between 14.5 and 15.5 J/K. Since ΔSsurr is -14.5 J/K, we can round it up to the nearest decimal place, which is 15 J/K. Therefore, the correct answer is between 14.5 and 15.5 J/K.
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Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer?
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Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer?.
Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer?.
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Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer?, a detailed solution for Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer? has been provided alongside types of Consider an isothermal reversible compression of one mole of an ideal gas in which the pressure of system is increased from 5 atm to 30 atm at 300 K. The entropy change of surrounding in J/K is___? (rounded up to first decimal place):Correct answer is between '14.5,15.5'. Can you explain this answer? theory, EduRev gives you an
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