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The reaction of anhydrous FeCl2 with sodium-pentadienyl in ether gives an air-stable diamagnetic orange solid, which on oxidation gives an air-sensitive paramgnetic blue-green compound in solution.
The blue-green compound is _____________
The blue-green compound is _____________
Correct answer is '1'. Can you explain this answer?
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Reaction of Anhydrous FeCl2 with Sodium-Pentadienyl
The reaction of anhydrous FeCl2 with sodium-pentadienyl (C5H5Na) in ether results in the formation of an air-stable diamagnetic orange solid. This reaction can be represented as follows:
FeCl2 + 2 C5H5Na → Fe(C5H5)2 + 2 NaCl
Formation of Diamagnetic Orange Solid
The product of this reaction is an air-stable diamagnetic orange solid. Diamagnetic compounds have all electrons paired up and are not affected by magnetic fields. The orange color indicates the presence of a transition metal complex. In this case, the complex formed is bis(pentadienyl)iron(II) or Fe(C5H5)2. The orange color is likely due to the absorption of certain wavelengths of visible light by the complex.
Oxidation of the Orange Solid
When the orange solid is oxidized, it forms an air-sensitive paramagnetic blue-green compound in solution. Paramagnetic compounds have unpaired electrons and are attracted to magnetic fields. The oxidation of Fe(C5H5)2 can be represented as follows:
2 Fe(C5H5)2 + O2 → 2 Fe(C5H5)3
The oxidation state of iron increases from +2 to +3 in this reaction. The blue-green color of the compound is likely due to a different electronic transition compared to the orange complex. The presence of unpaired electrons in the paramagnetic compound makes it sensitive to air, as oxygen can react with the unpaired electrons.
Summary
In summary, the reaction of anhydrous FeCl2 with sodium-pentadienyl in ether produces an air-stable diamagnetic orange solid, which is a bis(pentadienyl)iron(II) complex. When this orange solid is oxidized, it forms an air-sensitive paramagnetic blue-green compound in solution, which is likely a bis(pentadienyl)iron(III) complex.
The reaction of anhydrous FeCl2 with sodium-pentadienyl (C5H5Na) in ether results in the formation of an air-stable diamagnetic orange solid. This reaction can be represented as follows:
FeCl2 + 2 C5H5Na → Fe(C5H5)2 + 2 NaCl
Formation of Diamagnetic Orange Solid
The product of this reaction is an air-stable diamagnetic orange solid. Diamagnetic compounds have all electrons paired up and are not affected by magnetic fields. The orange color indicates the presence of a transition metal complex. In this case, the complex formed is bis(pentadienyl)iron(II) or Fe(C5H5)2. The orange color is likely due to the absorption of certain wavelengths of visible light by the complex.
Oxidation of the Orange Solid
When the orange solid is oxidized, it forms an air-sensitive paramagnetic blue-green compound in solution. Paramagnetic compounds have unpaired electrons and are attracted to magnetic fields. The oxidation of Fe(C5H5)2 can be represented as follows:
2 Fe(C5H5)2 + O2 → 2 Fe(C5H5)3
The oxidation state of iron increases from +2 to +3 in this reaction. The blue-green color of the compound is likely due to a different electronic transition compared to the orange complex. The presence of unpaired electrons in the paramagnetic compound makes it sensitive to air, as oxygen can react with the unpaired electrons.
Summary
In summary, the reaction of anhydrous FeCl2 with sodium-pentadienyl in ether produces an air-stable diamagnetic orange solid, which is a bis(pentadienyl)iron(II) complex. When this orange solid is oxidized, it forms an air-sensitive paramagnetic blue-green compound in solution, which is likely a bis(pentadienyl)iron(III) complex.
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The reaction of anhydrous FeCl2 with sodium-pentadienyl in ether gives an air-stable diamagnetic orange solid, which on oxidation gives an air-sensitive paramgnetic blue-green compound in solution.The blue-green compound is _____________Correct answer is '1'. Can you explain this answer?
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