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Time interval between two successive maxima of sound waves with frequencies v1 and v2 is given by
  • a)
    v1/v2
  • b)
    1/ (v1 - v2)
  • c)
    v1 = v2 = 0
  • d)
    v1 - v2
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
Time interval between two successive maxima of sound waves with freque...
As we know time interval will have dimensions of time so check in option for dimension of time.
Dimensions of v is "per second" or [T-1]
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Time interval between two successive maxima of sound waves with freque...
Explanation:

Let us assume that the two successive maxima of sound waves with frequencies v1 and v2 are observed at intervals of time t1 and t2, respectively.

Therefore, the time interval between two successive maxima can be given as:

t = t2 - t1

Now, we know that the time period of a wave is given as the time taken by a wave to complete one oscillation. Therefore, the time period of sound wave with frequency v1 can be given as:

T1 = 1/v1

Similarly, the time period of sound wave with frequency v2 can be given as:

T2 = 1/v2

Now, let us assume that the two successive maxima of sound waves with frequencies v1 and v2 coincide at a particular instant of time. Therefore, the time interval between two successive maxima can be given as:

t = T1 = T2

Substituting the values of T1 and T2, we get:

t = 1/v1 - 1/v2

On simplifying the above equation, we get:

t = (v2 - v1)/v1v2

Therefore, the time interval between two successive maxima of sound waves with frequencies v1 and v2 is given by option B:

t = 1/(v1 - v2)
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