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Find thw value of sin18?
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Find thw value of sin18?
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Let theeta = 18*. Then,
5 theeta = 90*
2 theeta + 3 theeta = 90*
2 theeta = 90* - 3 theeta
sin 2 theeta = sin(90* - 3 theeta)
sin 2 theeta = cos 3 theeta
2 sin theeta cos theeta = 4 cos3 theeta - 3 cos theeta
cos theeta(2 sin theeta - 4 cos2 theeta + 3) = 0
2 sin theeta - 4 cos2 theeta + 3 = 0
2 sin theeta - 4(1- sin2 theeta) + 3 = 0
4 sin2 theeta + 2 sin theeta - 1 = 0
sin theeta = - 2 +- root over 4+16 (divided by) 8
simplify & then u will get that the value of sin 18* comes out to be root 5 - 1(divided by) 4
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Find thw value of sin18?
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