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When a reduced cytochrome transfers an electron from its Fe(II) to the bound O2:
- a)The bond order or O2 is reduced by one and ν02 decreases.
- b)A metal bound superoxide is formed and ν02 decrease.
- c)A metal bound superoxide is formed and ν02 increase.
- d)The bond order or O2 is reduced by one and ν02 increases.
Correct answer is option 'B'. Can you explain this answer?
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Most Upvoted Answer
When a reduced cytochrome transfers an electron from its Fe(II) to the...
Explanation:
When a reduced cytochrome transfers an electron from its Fe(II) to the bound O2, a metal-bound superoxide is formed and O2 decreases. This can be explained as follows:
Formation of Metal-Bound Superoxide:
When a reduced cytochrome transfers an electron to the bound O2, the O2 molecule becomes superoxide (O2-), which is bound to the metal ion (Fe(III)) in the cytochrome. The Fe(III)-superoxide complex is stabilized by coordination of the superoxide to the metal ion through one of its oxygen atoms. This complex is a powerful oxidizing agent and can react with other molecules, such as proteins and lipids, causing damage to cells.
Decrease in O2:
When the electron is transferred from the cytochrome to the O2 molecule, the bond order of O2 is reduced by one, which means that the O-O bond is weakened. This weakens the O2 molecule, making it more reactive and prone to react with other molecules. As a result, the O2 molecule decreases in concentration.
Conclusion:
Thus, when a reduced cytochrome transfers an electron from its Fe(II) to the bound O2, a metal-bound superoxide is formed, and O2 decreases in concentration.
When a reduced cytochrome transfers an electron from its Fe(II) to the bound O2, a metal-bound superoxide is formed and O2 decreases. This can be explained as follows:
Formation of Metal-Bound Superoxide:
When a reduced cytochrome transfers an electron to the bound O2, the O2 molecule becomes superoxide (O2-), which is bound to the metal ion (Fe(III)) in the cytochrome. The Fe(III)-superoxide complex is stabilized by coordination of the superoxide to the metal ion through one of its oxygen atoms. This complex is a powerful oxidizing agent and can react with other molecules, such as proteins and lipids, causing damage to cells.
Decrease in O2:
When the electron is transferred from the cytochrome to the O2 molecule, the bond order of O2 is reduced by one, which means that the O-O bond is weakened. This weakens the O2 molecule, making it more reactive and prone to react with other molecules. As a result, the O2 molecule decreases in concentration.
Conclusion:
Thus, when a reduced cytochrome transfers an electron from its Fe(II) to the bound O2, a metal-bound superoxide is formed, and O2 decreases in concentration.
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When a reduced cytochrome transfers an electron from its Fe(II) to the bound O2:a)The bond order or O2 is reduced by one and ν02 decreases.b)A metal bound superoxide is formed and ν02 decrease.c)A metal bound superoxide is formed and ν02 increase.d)The bond order or O2 is reduced by one and ν02 increases.Correct answer is option 'B'. Can you explain this answer?
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