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The reversible reaction A ↔ B is first order in both the directions. The forward and reversed rate constants are 4.2×10-4 s-1 and 1.04×10-3 s-1 respectively. The relaxation time (rounded up to first decimal place) for this reaction, in seconds, in temperature experiment is_____?
    Correct answer is between '683.0,686.0'. Can you explain this answer?
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    The reversible reaction A ↔ B is first order in both the directio...
    Ans.

    Method to Solve :

    We know very well that forward reaction is usually more thermodynamically favorable compared with the reverse reaction and thus the relationship k1>=k2 maintains between the rate constants.
    Given that:
    forward reaction kf = 2.38 X 10^-4
    and Kb =8.15 X 10^-5;  
    Kc= kf/Kb.
    Thus Kc = 2.38 X 10^-4/8.15 X 10^-5 = 2.9~=3.
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    The reversible reaction A ↔ B is first order in both the directio...
    The reversible reaction A is a chemical reaction that can proceed in both the forward and backward directions. This means that the reactants can form products, but the products can also react to form the original reactants.

    In a reversible reaction, the reaction reaches a state of equilibrium where the forward and backward reactions occur at the same rate. This means that the concentrations of the reactants and products remain constant over time.

    The equilibrium constant, represented by K, is a measure of the ratio of the concentrations of the products to the concentrations of the reactants at equilibrium. It can be used to determine the extent to which the reaction proceeds in either the forward or backward direction.

    Reversible reactions are commonly represented using a double arrow (↔) to indicate that the reaction can occur in both directions. The forward reaction is typically represented by an arrow pointing to the right (→), while the backward reaction is represented by an arrow pointing to the left (←).

    Reversible reactions are important in many chemical processes and are used in various industries, such as in the production of ammonia, the Haber-Bosch process, and in the formation and breakdown of ATP in biological systems.
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    The reversible reaction A ↔ B is first order in both the directions. The forward and reversed rate constants are 4.2×10-4 s-1 and 1.04×10-3 s-1 respectively. The relaxation time (rounded up to first decimal place) for this reaction, in seconds, in temperature experiment is_____?Correct answer is between '683.0,686.0'. Can you explain this answer?
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