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The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 100 V is applied between two electrodes separated by 2 cm. The mobility of Li+ ion in water is,

  • a)
    4 × 10–4 cm2 s–1 V–1

  • b)
    1 × 10–4 s–1 V–1

  • c)
    4 V cm2 s–1

  • d)
    2.5 × 105 V s cm–2

Correct answer is option 'A'. Can you explain this answer?
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The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 1...
Velocity and Mobility of Li+ ion in Water

Velocity Calculation:

- Given: Voltage (V) = 100 V, Distance (d) = 2 cm, Velocity (v) = 2 x 10^2 cm/sec
- Velocity can be calculated using the formula v = V/d
- Substituting the values, v = 100/2 = 50 cm/sec

Mobility Calculation:

- Mobility is defined as the ratio of velocity to the electric field strength.
- Electric field strength (E) can be calculated using the formula E = V/d
- Substituting the values, E = 100/2 = 50 V/cm
- Mobility (u) = v/E
- Substituting the values, u = 50/50 = 1 cm^2/secV
- Since the unit of mobility is cm^2/secV, the answer needs to be converted to cm^2 s^-1 V^-1
- Multiplying by 10^4, u = 1 x 10^4 cm^2 s^-1 V^-1

Therefore, the correct answer is option A) 4 x 10^4 cm^2 s^-1 V^-1.
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The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 100 V is applied between two electrodes separated by 2 cm. The mobility of Li+ ion in water is,a)4 × 10–4 cm2 s–1 V–1b)1 × 10–4 s–1 V–1c)4 V cm2 s–1d)2.5 × 105 V s cm–2Correct answer is option 'A'. Can you explain this answer?
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The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 100 V is applied between two electrodes separated by 2 cm. The mobility of Li+ ion in water is,a)4 × 10–4 cm2 s–1 V–1b)1 × 10–4 s–1 V–1c)4 V cm2 s–1d)2.5 × 105 V s cm–2Correct answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 100 V is applied between two electrodes separated by 2 cm. The mobility of Li+ ion in water is,a)4 × 10–4 cm2 s–1 V–1b)1 × 10–4 s–1 V–1c)4 V cm2 s–1d)2.5 × 105 V s cm–2Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 100 V is applied between two electrodes separated by 2 cm. The mobility of Li+ ion in water is,a)4 × 10–4 cm2 s–1 V–1b)1 × 10–4 s–1 V–1c)4 V cm2 s–1d)2.5 × 105 V s cm–2Correct answer is option 'A'. Can you explain this answer?.
Solutions for The velocity of Li+ ion in water is 2 × 10–2 cm/sec when 100 V is applied between two electrodes separated by 2 cm. The mobility of Li+ ion in water is,a)4 × 10–4 cm2 s–1 V–1b)1 × 10–4 s–1 V–1c)4 V cm2 s–1d)2.5 × 105 V s cm–2Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
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