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The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially empty hash table of length 7 using quadratic probing with hash function h(k)= k mod 7. Find the maximum number of iteration (i) to solve collision.
    Correct answer is '3'. Can you explain this answer?
    Verified Answer
    The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially emp...
    If slot hash(x) % S is full, then use (hash(x) + 1*1) % S for next iteration use (hash(x) + 2*2)
    For ith iteration use (hash(x) + i*i)
    h(25) = 25 mod 7 = 4
    h(78) = 78 mod 7 = 1
    h(15) = 15 mod 7 = 1 → 15 + 1 × 1 mod 7 = 2
    h(109) = 109 mod 7 = 4 → 109 + 1 × 1 mod 7 = 5
    h(50) = 50 mod 7 = 1 → 50 + 1 × 1 mod 7 = 2 → 50 + 2 × 2 mod 7 = 5 → 50 + 3 × 3 mod 7 = 3
    h(6) = 6 mod 7 = 6
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    The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially emp...
    Explanation:

    • Quadratic probing is a collision resolution technique that uses a quadratic function to find the next available slot in the hash table.

    • The hash function used is h(k) = k mod 7, which maps each key to a slot in the hash table.

    • The keys 25, 78, 15, 109, 50, and 6 are inserted into the hash table using quadratic probing.

    • When there is a collision, quadratic probing uses the formula (i^2 + i) / 2 to find the next available slot.

    • The maximum number of iterations required to solve a collision is given by the formula (m-1)/2, where m is the size of the hash table.

    • Here, the size of the hash table is 7, so the maximum number of iterations required is (7-1)/2 = 3.

    • Therefore, the correct answer is 3.

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    The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially empty hash table of length 7 using quadratic probing with hash function h(k)= k mod 7. Find the maximum number of iteration (i) to solve collision.Correct answer is '3'. Can you explain this answer?
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