Computer Science Engineering (CSE) Exam > Computer Science Engineering (CSE) Questions > The keys 25, 78, 15, 109, 50, and 6 are inser...
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The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially empty hash table of length 7 using quadratic probing with hash function h(k)= k mod 7. Find the maximum number of iteration (i) to solve collision.
Correct answer is '3'. Can you explain this answer?
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Verified Answer
The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially emp...
If slot hash(x) % S is full, then use (hash(x) + 1*1) % S for next iteration use (hash(x) + 2*2)
For ith iteration use (hash(x) + i*i)
h(25) = 25 mod 7 = 4
h(78) = 78 mod 7 = 1
h(15) = 15 mod 7 = 1 → 15 + 1 × 1 mod 7 = 2
h(109) = 109 mod 7 = 4 → 109 + 1 × 1 mod 7 = 5
h(50) = 50 mod 7 = 1 → 50 + 1 × 1 mod 7 = 2 → 50 + 2 × 2 mod 7 = 5 → 50 + 3 × 3 mod 7 = 3
h(6) = 6 mod 7 = 6
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The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially emp...
Explanation:
- Quadratic probing is a collision resolution technique that uses a quadratic function to find the next available slot in the hash table.
- The hash function used is h(k) = k mod 7, which maps each key to a slot in the hash table.
- The keys 25, 78, 15, 109, 50, and 6 are inserted into the hash table using quadratic probing.
- When there is a collision, quadratic probing uses the formula (i^2 + i) / 2 to find the next available slot.
- The maximum number of iterations required to solve a collision is given by the formula (m-1)/2, where m is the size of the hash table.
- Here, the size of the hash table is 7, so the maximum number of iterations required is (7-1)/2 = 3.
- Therefore, the correct answer is 3.
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The keys 25, 78, 15, 109, 50, and 6 are inserted into an initially empty hash table of length 7 using quadratic probing with hash function h(k)= k mod 7. Find the maximum number of iteration (i) to solve collision.Correct answer is '3'. Can you explain this answer?
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