Computer Science Engineering (CSE) Exam  >  Computer Science Engineering (CSE) Questions  >  Find the probability of a number which is div... Start Learning for Free
Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.
  • a)
    0.47
  • b)
    0.35
  • c)
    0.27
  • d)
    0.58
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
Find the probability of a number which is divisible by either 5 or 3 o...
The First 500 Natural Odd numbers are given as 1,3,5,7,…………….999. 
The Numbers divisible by 3 from the above list are given as 3,9,15,21…………999 
The above series is in Arithmetic progression,
Tn = a+(n−1)d
999 = 3+(n3−1)6 ⇒ n3 = 167 
So total Numbers which are divisible by 3 in the given list is, n3 = 167 
The Numbers divisible by 5 from the above list are given as 55,15,25,35…………99 
The above series is in Arithmetic progression,
Tn = a+(n−1)d
995 = 5+(n5−1)10 ⇒ n5 = 100 
So total Numbers which are divisible by 5 in the given list is, n3 = 100.
The Numbers divisible by 15 from the above list are given as 15,45,75,105…………975 
The above series is in Arithmetic progression,
Tn = a+(n−1)d
975 = 15+(n15−1)30 ⇒ n15 = 33 
So total Numbers which are divisible by 3 in the given list is, n3 = 33 
So Required Probability p = p(n3)+p(n5)−p(n15) = = 0.468
View all questions of this test
Most Upvoted Answer
Find the probability of a number which is divisible by either 5 or 3 o...
Probability of a number divisible by either 5 or 3 out of the first 500 natural Odd Numbers

To find the probability of a number divisible by either 5 or 3 out of the first 500 natural odd numbers, we need to determine the count of numbers that are divisible by either 5 or 3, and then divide it by the total count of numbers.

Count of numbers divisible by 5:
To find the count of numbers divisible by 5, we need to divide the last number divisible by 5 (which is less than or equal to 500) by 5.

The last number divisible by 5 is 495 (5 * 99), so the count of numbers divisible by 5 is 99.

Count of numbers divisible by 3:
To find the count of numbers divisible by 3, we need to divide the last number divisible by 3 (which is less than or equal to 500) by 3.

The last number divisible by 3 is 495 (3 * 165), so the count of numbers divisible by 3 is 165.

Count of numbers divisible by both 5 and 3 (i.e., divisible by 15):
To find the count of numbers divisible by both 5 and 3, we need to divide the last number divisible by 15 (which is less than or equal to 500) by 15.

The last number divisible by 15 is 495 (15 * 33), so the count of numbers divisible by both 5 and 3 is 33.

Count of numbers divisible by either 5 or 3:
To find the count of numbers divisible by either 5 or 3, we need to add the count of numbers divisible by 5 and the count of numbers divisible by 3, and then subtract the count of numbers divisible by both 5 and 3.

Count of numbers divisible by either 5 or 3 = Count of numbers divisible by 5 + Count of numbers divisible by 3 - Count of numbers divisible by both 5 and 3
= 99 + 165 - 33
= 231

Probability:
The total count of numbers in the given range (first 500 natural odd numbers) can be calculated by dividing the range by 2 (since it's the count of odd numbers), so the total count is 500/2 = 250.

The probability of a number being divisible by either 5 or 3 is the count of numbers divisible by either 5 or 3 divided by the total count of numbers.

Probability = Count of numbers divisible by either 5 or 3 / Total count of numbers
= 231 / 250
≈ 0.924

Rounding to two decimal places, the probability is approximately 0.92, which is not one of the given options.

Therefore, the correct answer is not among the options provided.
Explore Courses for Computer Science Engineering (CSE) exam

Similar Computer Science Engineering (CSE) Doubts

Top Courses for Computer Science Engineering (CSE)

Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer?
Question Description
Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? for Computer Science Engineering (CSE) 2024 is part of Computer Science Engineering (CSE) preparation. The Question and answers have been prepared according to the Computer Science Engineering (CSE) exam syllabus. Information about Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Computer Science Engineering (CSE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer?.
Solutions for Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Computer Science Engineering (CSE). Download more important topics, notes, lectures and mock test series for Computer Science Engineering (CSE) Exam by signing up for free.
Here you can find the meaning of Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer?, a detailed solution for Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? has been provided alongside types of Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Find the probability of a number which is divisible by either 5 or 3 out of first 500 natural Odd Numbers.a)0.47b)0.35c)0.27d)0.58Correct answer is option 'A'. Can you explain this answer? tests, examples and also practice Computer Science Engineering (CSE) tests.
Explore Courses for Computer Science Engineering (CSE) exam

Top Courses for Computer Science Engineering (CSE)

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev