Class 12 Exam > Class 12 Questions > CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3...
Start Learning for Free
CH3=CH2CH3 + H – I → CH3CH2CH2I + CH3CHICH3 (major). This reaction is
- a)Sandmeyer’s reaction
- b)Markovnikov’s rule.
- c)free radical halogenations
- d)Finkelstein reaction
Correct answer is option 'B'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This react...
This is electrophilic addition reaction following Markovnikoffs rule.
Most Upvoted Answer
CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This react...
Explanation:
The given reaction involves the conversion of an alkene (CH3CH=CH2) to an alkyl halide (CH3CH2CH2I) through the addition of a halogen (Iodine, I) in the presence of a Lewis acid catalyst (AlCl3). This reaction follows the Markovnikov's rule.
Markovnikov's Rule:
According to the Markovnikov's rule, when a hydrogen halide (HX) is added to an alkene, the hydrogen atom adds to the carbon atom with fewer alkyl substituents, while the halide adds to the carbon atom with more alkyl substituents. In other words, the hydrogen adds to the less substituted carbon, while the halide adds to the more substituted carbon.
Reaction Mechanism:
The reaction proceeds through the following steps:
1. Formation of a carbocation:
The double bond in the alkene attacks the electrophilic iodine atom, breaking the iodine-halogen bond and forming a carbocation intermediate.
CH3CH=CH2 + I2 → CH3CHI-CH2• + I-
2. Addition of iodide ion:
The iodide ion (I-) acts as a nucleophile and attacks the carbocation, resulting in the addition of iodide to the more substituted carbon atom.
CH3CHI-CH2• + I- → CH3CHI-CH2I
3. Rearrangement (optional):
In some cases, rearrangement of the carbocation may occur to form a more stable carbocation before the addition of the iodide ion.
4. Formation of the alkyl iodide:
The final product is an alkyl iodide (CH3CH2CH2I), where the iodide has added to the more substituted carbon atom.
Conclusion:
The given reaction follows the Markovnikov's rule, where the iodide ion adds to the more substituted carbon atom. Therefore, the correct answer is option 'B' - Markovnikov's rule.
The given reaction involves the conversion of an alkene (CH3CH=CH2) to an alkyl halide (CH3CH2CH2I) through the addition of a halogen (Iodine, I) in the presence of a Lewis acid catalyst (AlCl3). This reaction follows the Markovnikov's rule.
Markovnikov's Rule:
According to the Markovnikov's rule, when a hydrogen halide (HX) is added to an alkene, the hydrogen atom adds to the carbon atom with fewer alkyl substituents, while the halide adds to the carbon atom with more alkyl substituents. In other words, the hydrogen adds to the less substituted carbon, while the halide adds to the more substituted carbon.
Reaction Mechanism:
The reaction proceeds through the following steps:
1. Formation of a carbocation:
The double bond in the alkene attacks the electrophilic iodine atom, breaking the iodine-halogen bond and forming a carbocation intermediate.
CH3CH=CH2 + I2 → CH3CHI-CH2• + I-
2. Addition of iodide ion:
The iodide ion (I-) acts as a nucleophile and attacks the carbocation, resulting in the addition of iodide to the more substituted carbon atom.
CH3CHI-CH2• + I- → CH3CHI-CH2I
3. Rearrangement (optional):
In some cases, rearrangement of the carbocation may occur to form a more stable carbocation before the addition of the iodide ion.
4. Formation of the alkyl iodide:
The final product is an alkyl iodide (CH3CH2CH2I), where the iodide has added to the more substituted carbon atom.
Conclusion:
The given reaction follows the Markovnikov's rule, where the iodide ion adds to the more substituted carbon atom. Therefore, the correct answer is option 'B' - Markovnikov's rule.
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer?
Question Description
CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer?.
CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer?.
Solutions for CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice CH3=CH2CH3+ H – I →CH3CH2CH2I+CH3CHICH3(major). This reaction isa)Sandmeyer’s reactionb)Markovnikov’s rule.c)free radical halogenationsd)Finkelstein reactionCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup