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In which of the following complexes, the nickel metal is in the highest oxidation state?
- a)K2NiF6
- b)NI(CO)4
- c)K4[Ni(CN)6]
- d)[Ni(NH3)6](BF4)2]
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
In which of the following complexes, the nickel metal is in the highes...
In A Ni has +4 oxidation state.
Most Upvoted Answer
In which of the following complexes, the nickel metal is in the highes...
(a) 2(+1) + x + 6(-1) = 0 ==> x = +4
(b) oxidation number on Ni = 0 (since CO is a neutral molecule)
(c) 4(+1) + x + 6(-1) = 0 ==> x = +2
(d) x + 6(0) + 2(-1) = 0 ==> x = +2 (since ammonia is a neutral molecule)
So, Ni has maximum oxidation state in first case
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Community Answer
In which of the following complexes, the nickel metal is in the highes...
Nickel Metal in Highest Oxidation State
Explanation:
In order to determine the highest oxidation state of nickel in the given complexes, we need to consider the oxidation states of all the other elements and the overall charge of the complex.
a) K2NiF6:
- In this complex, the overall charge is 0 (since K has a +1 charge and F has a -1 charge).
- The oxidation state of K is +1 and F is -1.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
2(+1) + x + 6(-1) = 0
2 + x - 6 = 0
x - 4 = 0
x = +4
b) Ni(CO)4:
- In this complex, the overall charge is 0 (since CO has a neutral charge).
- The oxidation state of C is +2 and O is -2.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
x + 4(0) = 0
x = 0
c) K4[Ni(CN)6]:
- In this complex, the overall charge is 0 (since K has a +1 charge, C has a +2 charge, and N has a -3 charge).
- The oxidation state of K is +1, C is +2, and N is -3.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
4(+1) + x + 6(-3) = 0
4 + x - 18 = 0
x - 14 = 0
x = +14
d) [Ni(NH3)6](BF4)2:
- In this complex, the overall charge is 0 (since NH3 has a neutral charge and BF4 has a -2 charge).
- The oxidation state of N is -3 and H is +1.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
x + 6(0) + 2(-2) = 0
x - 4 = 0
x = +4
Conclusion:
Based on the calculations, the highest oxidation state of nickel is +4, which is present in the complex K2NiF6 (option A).
Explanation:
In order to determine the highest oxidation state of nickel in the given complexes, we need to consider the oxidation states of all the other elements and the overall charge of the complex.
a) K2NiF6:
- In this complex, the overall charge is 0 (since K has a +1 charge and F has a -1 charge).
- The oxidation state of K is +1 and F is -1.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
2(+1) + x + 6(-1) = 0
2 + x - 6 = 0
x - 4 = 0
x = +4
b) Ni(CO)4:
- In this complex, the overall charge is 0 (since CO has a neutral charge).
- The oxidation state of C is +2 and O is -2.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
x + 4(0) = 0
x = 0
c) K4[Ni(CN)6]:
- In this complex, the overall charge is 0 (since K has a +1 charge, C has a +2 charge, and N has a -3 charge).
- The oxidation state of K is +1, C is +2, and N is -3.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
4(+1) + x + 6(-3) = 0
4 + x - 18 = 0
x - 14 = 0
x = +14
d) [Ni(NH3)6](BF4)2:
- In this complex, the overall charge is 0 (since NH3 has a neutral charge and BF4 has a -2 charge).
- The oxidation state of N is -3 and H is +1.
- Let the oxidation state of Ni be x.
- Using the oxidation states of the other elements, we can write the equation as:
x + 6(0) + 2(-2) = 0
x - 4 = 0
x = +4
Conclusion:
Based on the calculations, the highest oxidation state of nickel is +4, which is present in the complex K2NiF6 (option A).
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