Which of the following ion has smallest radii?a)V2+b)Ni2+c)Mn2+d)Ti2+C...
In period when we move from left to right in a period atomic radii 1st decreases till nickel then starts increasing so Ni2+ has smallest radii.
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Which of the following ion has smallest radii?a)V2+b)Ni2+c)Mn2+d)Ti2+C...
Explanation:
The ionic radius of an ion is defined as the distance between the center of the nucleus to the outermost shell of the ion. The effective nuclear charge, which is the attraction between the positively charged nucleus and the negatively charged electrons in the ion, determines the ionic radius.
Factors affecting ionic radius:
- Nuclear charge
- Number of electrons
- Energy level
Comparison of ions:
a) V2+ has a configuration of [Ar] 3d3, while b) Ni2+ has a configuration of [Ar] 3d8. c) Mn2+ has a configuration of [Ar] 3d5, and d) Ti2+ has a configuration of [Ar] 3d2.
Since all the ions have the same number of electrons in their 3d subshell, the nuclear charge becomes the determining factor. As the nuclear charge increases, the electrons are pulled closer to the nucleus, resulting in a smaller ionic radius.
Conclusion:
Out of the given options, Ni2+ has the highest nuclear charge, resulting in the smallest ionic radius. Therefore, the correct answer is option B) Ni2+.