Explanation:
The specific conductance of an electrolytic solution is directly proportional to the concentration of ions present in it. Hence, the solution with the least concentration of ions will have the least specific conductance.

Calculations:
a) 0.002 N solution
The concentration of ions in a 0.002 N solution is = 0.002 x 2 = 0.004 M (since the solution contains 2 ions)
The specific conductance of the solution can be calculated using the equation:
Specific conductance = Conductance / (cell constant x concentration)
Assuming a cell constant of 1, the specific conductance of the solution is:
Specific conductance = Conductance / 0.004
b) 2 N solution
The concentration of ions in a 2 N solution is = 2 x 2 = 4 M (since the solution contains 2 ions)
The specific conductance of the solution can be calculated using the equation:
Specific conductance = Conductance / (cell constant x concentration)
Assuming a cell constant of 1, the specific conductance of the solution is:
Specific conductance = Conductance / 4
c) 0.02 N solution
The concentration of ions in a 0.02 N solution is = 0.02 x 2 = 0.04 M (since the solution contains 2 ions)
The specific conductance of the solution can be calculated using the equation:
Specific conductance = Conductance / (cell constant x concentration)
Assuming a cell constant of 1, the specific conductance of the solution is:
Specific conductance = Conductance / 0.04
d) 0.2 N solution
The concentration of ions in a 0.2 N solution is = 0.2 x 2 = 0.4 M (since the solution contains 2 ions)
The specific conductance of the solution can be calculated using the equation:
Specific conductance = Conductance / (cell constant x concentration)
Assuming a cell constant of 1, the specific conductance of the solution is:
Specific conductance = Conductance / 0.4

Conclusion:
From the above calculations, it can be seen that the specific conductance of a 0.002 N solution will be the least, since it has the lowest concentration of ions. Hence, option A is the correct answer.