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The equilibrium constant is 6.0 × 10–4 for the N2O2→ 2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:
- a)10.9 × 10–3 mol/L
- b)1.09 × 10–3 mol/L
- c)10.9 × 10–5 mol/L
- d)1.09 × 10–5 mol/L
Correct answer is option 'B'. Can you explain this answer?
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The equilibrium constant is 6.0 × 10–4 for the N2O2→2...
The equilibrium constant (K) is a measure of the ratio of product concentrations to reactant concentrations at equilibrium. It is a dimensionless quantity that quantifies the extent to which a reaction proceeds.
In this case, if the equilibrium constant is 6.0, it means that at equilibrium, the concentration of products is 6 times greater than the concentration of reactants. This indicates that the reaction is more product-favored, meaning that the reaction proceeds significantly in the forward direction to form products.
It is important to note that the equilibrium constant is temperature-dependent and can vary depending on the specific reaction.
In this case, if the equilibrium constant is 6.0, it means that at equilibrium, the concentration of products is 6 times greater than the concentration of reactants. This indicates that the reaction is more product-favored, meaning that the reaction proceeds significantly in the forward direction to form products.
It is important to note that the equilibrium constant is temperature-dependent and can vary depending on the specific reaction.
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The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer?
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The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer?.
The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer?.
Solutions for The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice The equilibrium constant is 6.0 × 10–4 for the N2O2→2NO reaction. If the concentration of nitrogen is 0.10 mol/L and concentration of oxygen is 0.20 mol/L at equilibrium. Then the concentration of nitric oxide at equilibrium is:a)10.9 × 10–3 mol/Lb)1.09 × 10–3 mol/Lc)10.9 × 10–5 mol/Ld)1.09 × 10–5 mol/LCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Chemistry tests.
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