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A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:
Correct answer is between '66,68'. Can you explain this answer?
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A solution containing 30g of non-volatile solute in exactly 90g of wat...
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A solution containing 30g of non-volatile solute in exactly 90g of wat...
Given:
- Mass of solute = 30g
- Mass of water = 90g
- Vapor pressure of solution = 21.85 mmHg
- Mass of additional water added = 18g
- Vapor pressure of resulting solution = 22.15 mmHg
- Temperature = 25°C
To find:
Molecular weight of the solute
Solution:
Step 1: Calculate the moles of solute in the original solution
We can calculate the moles of solute using the formula:
Moles of solute = Mass of solute / Molecular weight of solute
Given that the mass of solute is 30g, we need to find the molecular weight of the solute.
Step 2: Calculate the moles of water in the original solution
We can calculate the moles of water using the formula:
Moles of water = Mass of water / Molecular weight of water
Given that the mass of water is 90g, we know that the molecular weight of water is 18 g/mol.
Step 3: Calculate the mole fraction of solute in the original solution
The mole fraction of solute can be calculated using the formula:
Mole fraction of solute = Moles of solute / (Moles of solute + Moles of water)
Step 4: Calculate the mole fraction of water in the original solution
The mole fraction of water can be calculated using the formula:
Mole fraction of water = Moles of water / (Moles of solute + Moles of water)
Step 5: Calculate the vapor pressure of water in the original solution
The vapor pressure of water in the original solution can be calculated using Raoult's Law:
P_water = X_water * P°_water
Where:
P_water is the vapor pressure of water in the solution
X_water is the mole fraction of water in the solution
P°_water is the vapor pressure of pure water at the given temperature
Given that the vapor pressure of the solution is 21.85 mmHg, we can rearrange the equation to solve for X_water:
X_water = P_water / P°_water
Step 6: Calculate the vapor pressure of water in the resulting solution
We can follow the same steps as in Step 5 to calculate the vapor pressure of water in the resulting solution.
Step 7: Calculate the mole fraction of water in the resulting solution
Using the vapor pressure of water in the resulting solution and the vapor pressure of pure water at the given temperature, we can calculate the mole fraction of water in the resulting solution.
Step 8: Calculate the mole fraction of solute in the resulting solution
Using the mole fraction of water in the resulting solution, we can calculate the mole fraction of solute in the resulting solution.
Step 9: Calculate the moles of solute in the resulting solution
Using the mole fraction of solute in the resulting solution and the moles of water in the resulting solution, we can calculate the moles of solute in the resulting solution.
Step 10: Calculate the molecular weight of the solute
Finally, we can calculate the molecular
- Mass of solute = 30g
- Mass of water = 90g
- Vapor pressure of solution = 21.85 mmHg
- Mass of additional water added = 18g
- Vapor pressure of resulting solution = 22.15 mmHg
- Temperature = 25°C
To find:
Molecular weight of the solute
Solution:
Step 1: Calculate the moles of solute in the original solution
We can calculate the moles of solute using the formula:
Moles of solute = Mass of solute / Molecular weight of solute
Given that the mass of solute is 30g, we need to find the molecular weight of the solute.
Step 2: Calculate the moles of water in the original solution
We can calculate the moles of water using the formula:
Moles of water = Mass of water / Molecular weight of water
Given that the mass of water is 90g, we know that the molecular weight of water is 18 g/mol.
Step 3: Calculate the mole fraction of solute in the original solution
The mole fraction of solute can be calculated using the formula:
Mole fraction of solute = Moles of solute / (Moles of solute + Moles of water)
Step 4: Calculate the mole fraction of water in the original solution
The mole fraction of water can be calculated using the formula:
Mole fraction of water = Moles of water / (Moles of solute + Moles of water)
Step 5: Calculate the vapor pressure of water in the original solution
The vapor pressure of water in the original solution can be calculated using Raoult's Law:
P_water = X_water * P°_water
Where:
P_water is the vapor pressure of water in the solution
X_water is the mole fraction of water in the solution
P°_water is the vapor pressure of pure water at the given temperature
Given that the vapor pressure of the solution is 21.85 mmHg, we can rearrange the equation to solve for X_water:
X_water = P_water / P°_water
Step 6: Calculate the vapor pressure of water in the resulting solution
We can follow the same steps as in Step 5 to calculate the vapor pressure of water in the resulting solution.
Step 7: Calculate the mole fraction of water in the resulting solution
Using the vapor pressure of water in the resulting solution and the vapor pressure of pure water at the given temperature, we can calculate the mole fraction of water in the resulting solution.
Step 8: Calculate the mole fraction of solute in the resulting solution
Using the mole fraction of water in the resulting solution, we can calculate the mole fraction of solute in the resulting solution.
Step 9: Calculate the moles of solute in the resulting solution
Using the mole fraction of solute in the resulting solution and the moles of water in the resulting solution, we can calculate the moles of solute in the resulting solution.
Step 10: Calculate the molecular weight of the solute
Finally, we can calculate the molecular
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A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer?
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A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer?.
A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer?.
Solutions for A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer?, a detailed solution for A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? has been provided alongside types of A solution containing 30g of non-volatile solute in exactly 90g of water has a vapor pressure of 21.85 mm of Hg at 25oC. Further 18g of water is then added to the solution. The resulting solution has then vapor pressure of 22.15 mmHg at same temp. M.wt. of solute will be:Correct answer is between '66,68'. Can you explain this answer? theory, EduRev gives you an
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