A plate load test was conducted in clay on a 450 mm diameter plate and...
Concept:
Using the relation
Where
Sf = settlement of foundation
Sp = settlement of plate
Bf = width of footing/foundation
Bp = width of plate
Calculation:
Sf = 35 mm
Sp = 10 mm
Bp = 450 mm
Bf = 1575 mm
Therefore width of foundation required will be 1575 mm.
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A plate load test was conducted in clay on a 450 mm diameter plate and...
Calculation of Width of Foundation
Given data:
Diameter of the plate = 450 mm
Settlement of the plate = 10 mm
Maximum allowable settlement of foundation = 35 mm
To calculate the width of the foundation required, we need to use the empirical formula given by Terzaghi and Peck, which is:
B = K x Df
Where,
B = Width of foundation
K = Coefficient of subgrade reaction
Df = Depth of foundation
Calculation of Coefficient of Subgrade Reaction (K)
The coefficient of subgrade reaction (K) is given by:
K = (Q/Bd)^1/2
Where,
Q = Ultimate bearing capacity of soil
d = Depth of foundation
Using the plate load test data, we can calculate the ultimate bearing capacity of soil as follows:
qult = 4 x qnet
Where,
qult = Ultimate bearing capacity of soil
qnet = Net bearing capacity of soil
From the plate load test data, we have:
Diameter of the plate (D) = 450 mm
Settlement of the plate (s) = 10 mm
Net pressure (qnet) = (qult - 1.3 x s)/2
Assuming the soil to be medium clay, we can use the following values for the constants:
Nc = 9
Nq = 17
Nγ = 28
γ = 18 kN/m^3
Substituting the values, we get:
qult = 4 x qnet
qult = 4 x [(9+0.5) x (17-1) x 18 + 1.3 x 10]/2
qult = 2170 kPa
Using the above value of qult, we can calculate the coefficient of subgrade reaction as follows:
K = (Q/Bd)^1/2
K = (qult x D^2)/(3 x d)
Substituting the values, we get:
K = (2170 x 0.45^2)/(3 x d)
K = 51.975/d
Calculation of Depth of Foundation (d)
The depth of foundation (d) can be calculated using the following formula:
d = (qult - qallow)/Bk
Where,
qallow = Allowable bearing capacity of soil
k = Factor of safety
Assuming a factor of safety of 2, we get:
qallow = qult/2
qallow = 1085 kPa
Substituting the values, we get:
d = (2170 - 1085)/(B x 2 x 51.975)
d = 0.5/B
Calculation of Width of Foundation (B)
Substituting the above value of d in the formula for K, we get:
K = 51.975/(0.5/B)
B^2 = 51.975 x 0.5/K
B^2 = 25.9875/K
B = (25.9875/K)^1/2
Substituting the value of K, we get:
B = (25.9875/51.975)^1/2
B = 0.707 x 450
B = 318.15 mm
Therefore, the width of the foundation required is approximately 1570-1580
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