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The edge length of a centred unit cubic cell is 508 pm. If the radius of the cation is 100 pm, the radius of the anion is [1996]

  • a)
    288 pm

  • b)
    398 pm

  • c)
    144 pm

  • d)
    618 pm

Correct answer is option 'C'. Can you explain this answer?
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The edge length of a centred unit cubic cell is 508 pm. If the radius ...
For fcc
2( rcation + ranion ) = 508 ( rcation + ranion )
= 254 ranion + 100 = 254 ,
⇒ ranion = 154
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The edge length of a centred unit cubic cell is 508 pm. If the radius of the cation is 100 pm, the radius of the anion is [1996]a)288 pmb)398 pmc)144 pmd)618 pmCorrect answer is option 'C'. Can you explain this answer?
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