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 In a Daniel cell, the oxidation and reduction halves occur at:
  • a)
    copper and zinc electrodes respectively
  • b)
    zinc and copper electrodes respectively
  • c)
    both occur at copper electrode respectively
  • d)
    both occur at zinc electrode respectively
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
In a Daniel cell, the oxidation and reduction halves occur at:a)copper...
Reduction occurs at the cathode which is made up of the element having higher reduction potential value . oxidation occurs at the anode made of the element having lower reduction potential value . copper has more reduction potential than xinc
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Community Answer
In a Daniel cell, the oxidation and reduction halves occur at:a)copper...
The correct answer is option 'B': zinc and copper electrodes respectively.

Explanation:
A Daniel cell is an electrochemical cell that consists of two half-cells connected by a salt bridge. The two half-cells are the oxidation half-cell and the reduction half-cell.

1. Oxidation Half-Cell:
In the oxidation half-cell, oxidation occurs. This means that electrons are lost by the electrode material and transferred to the external circuit. In the Daniel cell, the zinc electrode is the site of oxidation. Zinc atoms lose two electrons to form Zn2+ ions:
Zn(s) → Zn2+(aq) + 2e-

2. Reduction Half-Cell:
In the reduction half-cell, reduction occurs. This means that electrons are gained by the electrode material from the external circuit. In the Daniel cell, the copper electrode is the site of reduction. Copper(II) ions from the copper sulfate solution in the reduction half-cell gain two electrons to form copper atoms:
Cu2+(aq) + 2e- → Cu(s)

3. Overall Cell Reaction:
The overall cell reaction can be obtained by combining the oxidation and reduction half-reactions. Since the number of electrons lost in the oxidation half-reaction is equal to the number of electrons gained in the reduction half-reaction, the two half-reactions can be added together to obtain the overall cell reaction:
Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(s)

4. Cell Diagram:
The cell diagram for a Daniel cell is represented as:
Zn(s) | Zn2+(aq) || Cu2+(aq) | Cu(s)

In conclusion, in a Daniel cell, the oxidation half occurs at the zinc electrode and the reduction half occurs at the copper electrode. This allows for the flow of electrons from the zinc electrode to the copper electrode through the external circuit, generating an electric current.
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In a Daniel cell, the oxidation and reduction halves occur at:a)copper and zinc electrodes respectivelyb)zinc and copper electrodes respectivelyc)both occur at copper electrode respectivelyd)both occur at zinc electrode respectivelyCorrect answer is option 'B'. Can you explain this answer?
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