The volume of cylinder is 6358 cu cm and it's height is 28 cm find it'...
Answer:
radius = 8.5
csa of cylinder = 1496
explanation:
according to problem
volume of cylinder=6358
πr^2h=6358
22/7xr^2x28=6358
r^2x28=6358x7/22
r^2=72.25
r=8.5
csa of cylinder=2πrh
=2x22/7x8.5x28
=1496
This question is part of UPSC exam. View all Class 9 courses
The volume of cylinder is 6358 cu cm and it's height is 28 cm find it'...
Given:
- Volume of cylinder = 6358 cu cm
- Height of cylinder = 28 cm
To Find:
- Area of the cylinder
- Curved surface area (CSA) of the cylinder
Formula:
- Volume of a cylinder = π * r^2 * h
- Curved surface area of a cylinder = 2 * π * r * h
- Area of a cylinder = 2 * π * r * (r + h)
Solution:
Step 1: Find the radius of the cylinder
- The formula for the volume of a cylinder is given as: V = π * r^2 * h
- Rearranging the formula, we get: r = √(V / (π * h))
Given V = 6358 cu cm and h = 28 cm,
- Substituting the values in the formula, we have: r = √(6358 / (π * 28))
- Calculating the value, we find: r ≈ 9.03 cm
Step 2: Calculate the area of the cylinder
- The formula for the area of a cylinder is given as: A = 2 * π * r * (r + h)
Given r = 9.03 cm and h = 28 cm,
- Substituting the values in the formula, we have: A = 2 * π * 9.03 * (9.03 + 28)
- Calculating the value, we find: A ≈ 2308.75 sq cm
Therefore, the area of the cylinder is approximately 2308.75 square centimeters.
Step 3: Determine the curved surface area of the cylinder
- The formula for the curved surface area of a cylinder is given as: CSA = 2 * π * r * h
Given r = 9.03 cm and h = 28 cm,
- Substituting the values in the formula, we have: CSA = 2 * π * 9.03 * 28
- Calculating the value, we find: CSA ≈ 1600.06 sq cm
Therefore, the curved surface area of the cylinder is approximately 1600.06 square centimeters.
Summary:
- The area of the cylinder is approximately 2308.75 square centimeters.
- The curved surface area of the cylinder is approximately 1600.06 square centimeters.
To make sure you are not studying endlessly, EduRev has designed Class 9 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 9.