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Equation of the chord of the hyperbola 25x2 – 16y2 = 400 which is bisected at the point (6, 2) is
  • a)
    16x – 75y = 418
  • b)
    75x – 16y = 418
  • c)
    25x – 4y = 400
  • d)
    None of these
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Equation of the chord of the hyperbola 25x2–16y2= 400 which is b...
Given hyperbola is 25x2−16y2=400
If (6, 2) is the midpoint of the chord, then equation of chord is T = S1
​⇒25(6x)−16(2y)=25(36)−16(4)
⇒75x−16y=450−32
⇒75x−16y=418
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Most Upvoted Answer
Equation of the chord of the hyperbola 25x2–16y2= 400 which is b...
Given hyperbola is 25x2−16y2=400
If (6, 2) is the midpoint of the chord, then equation of chord is T = S1
​⇒25(6x)−16(2y)=25(36)−16(4)
⇒75x−16y=450−32
⇒75x−16y=418
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Community Answer
Equation of the chord of the hyperbola 25x2–16y2= 400 which is b...
Equation of the Chord of the Hyperbola:

Given Hyperbola Equation: 25x^2 - 16y^2 = 400

Bisected at the Point (6, 2):
The chord is bisected at the point (6, 2), which means the midpoint of the chord is (6, 2).

Midpoint Formula:
The midpoint formula for a line segment with endpoints (x1, y1) and (x2, y2) is:
Midpoint = ((x1 + x2)/2, (y1 + y2)/2)

Using Midpoint Formula:
Given point (6, 2) is the midpoint, we can find the other endpoint of the chord.

Equation of the Chord:
Once we have the two endpoints of the chord, we can find the equation of the chord using the two-point form of the equation of a line.

Options Analysis:
Now, we need to substitute the endpoints into the given options to see which equation satisfies the conditions.

Correct Answer: Option B) 75x - 16y = 418

Explanation:
By substituting the endpoints into option B, we can verify that this equation represents the chord that is bisected at the point (6, 2) for the given hyperbola.
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Equation of the chord of the hyperbola 25x2–16y2= 400 which is bisected at the point (6, 2) isa)16x –75y = 418b)75x –16y = 418c)25x –4y = 400d)None of theseCorrect answer is option 'B'. Can you explain this answer?
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Equation of the chord of the hyperbola 25x2–16y2= 400 which is bisected at the point (6, 2) isa)16x –75y = 418b)75x –16y = 418c)25x –4y = 400d)None of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Equation of the chord of the hyperbola 25x2–16y2= 400 which is bisected at the point (6, 2) isa)16x –75y = 418b)75x –16y = 418c)25x –4y = 400d)None of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equation of the chord of the hyperbola 25x2–16y2= 400 which is bisected at the point (6, 2) isa)16x –75y = 418b)75x –16y = 418c)25x –4y = 400d)None of theseCorrect answer is option 'B'. Can you explain this answer?.
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