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The ionization energy of H atom in its ground state is approximately 13.6 eV. The potential energy of He+, in its ground state is approximately:
  • a)
    –54.4 eV
  • b)
    –27.2 eV
  • c)
    –13.6 eV
  • d)
    –108.8 eV
Correct answer is option 'D'. Can you explain this answer?
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The ionization energy of H atom in its ground state is approximately 1...
The ionization energy of an atom is the energy required to remove an electron from the atom in its ground state. In the case of the hydrogen atom, the ionization energy is approximately 13.6 eV.

The potential energy of an atom in its ground state can be thought of as the energy required to separate the atom into its constituent particles (in this case, the nucleus and the electron(s)). In the case of helium (He), the ground state consists of two electrons orbiting the nucleus.

Since the ionization energy of hydrogen is approximately 13.6 eV, we can say that the potential energy of helium, in its ground state, is approximately twice that value. Therefore, the potential energy of helium, in its ground state, is approximately 27.2 eV.
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The ionization energy of H atom in its ground state is approximately 13.6 eV. The potential energy of He+, in its ground state is approximately:a)–54.4 eVb)–27.2 eVc)–13.6 eVd)–108.8 eVCorrect answer is option 'D'. Can you explain this answer?
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