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A cylinder confines 2.00 L gas under a pressure of 1.00 atm. The external pressure is also 1.00 atm. The gas is heated slowly, with the piston sliding freely outward to maintain the pressure of the gas close to 1.00 atm. Suppose the heating continues until a final volume of 3.50 L is reached. Calculate the work done on the gas.

 

  • a)
    -152 J

  • b)
    -112 J

  • c)
    -172 J

  • d)
    -132 J

Correct answer is option 'A'. Can you explain this answer?
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A cylinder confines 2.00 L gas under a pressure of 1.00 atm. The exter...




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A cylinder confines 2.00 L gas under a pressure of 1.00 atm. The exter...
To calculate the work done on the gas, we can use the formula:

Work = Pressure * Change in Volume

In this case, the pressure is constant at 1.00 atm and the initial volume is 2.00 L while the final volume is 3.50 L.

1. Calculate the change in volume:
Change in Volume = Final Volume - Initial Volume
Change in Volume = 3.50 L - 2.00 L
Change in Volume = 1.50 L

2. Calculate the work done on the gas:
Work = Pressure * Change in Volume
Work = 1.00 atm * 1.50 L
Work = 1.50 atm L

However, the unit for work is Joules (J), not atm L. We need to convert atm L to Joules.

1 atm L = 101.325 J
Therefore, 1.50 atm L = 1.50 * 101.325 J
Work = 151.9875 J

Rounding off the value to the correct significant figures, we get:
Work = -152 J

Therefore, the correct answer is option A) -152 J.
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Community Answer
A cylinder confines 2.00 L gas under a pressure of 1.00 atm. The exter...
W= - p(v2-v1)
= -1(3.50 - 2.00)
=-1(1.50)
= -1.50
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