Calculate number of atoms of the constituent element in 53g of Na2CO3.?

Question

Answer

Avagadro's constant states that 1 mole of any substance has 6.022 X 10^23molecules/atoms.

Find the number of moles of 53 g of Na2CO3:

molar mass Na2CO3 = 23 X 2 + 12 + 16 X 3 = (46+12+48) = 106

moles = mass/molar mass

= 53/106

= 0.5 moles

1 mole = 6.022 X10^23atoms

Then 0.5 moles = 6.022 X 10^23 X 0.5 atoms

= 3.011 X10^23 atoms of Na2CO3

Answer

Answer

Number of Atoms in 53g of Na2CO3

Given:
Mass of Na2CO3 = 53g

Step 1: Find the molar mass of Na2CO3
To calculate the number of atoms in a given mass, we need to know the molar mass of the compound. The molar mass is the sum of the atomic masses of all the elements in the compound.

Molar mass of Na = 22.99 g/mol (from periodic table)
Molar mass of C = 12.01 g/mol (from periodic table)
Molar mass of O = 16.00 g/mol (from periodic table)

Molar mass of Na2CO3 = (2 * 22.99 g/mol) + (1 * 12.01 g/mol) + (3 * 16.00 g/mol)
= 45.98 g/mol + 12.01 g/mol + 48.00 g/mol
= 105.99 g/mol

Step 2: Calculate the number of moles of Na2CO3
We can use the formula: moles = mass / molar mass

Number of moles of Na2CO3 = 53g / 105.99 g/mol
≈ 0.499 moles (rounded to three decimal places)

Step 3: Calculate the number of atoms of Na in 0.499 moles of Na2CO3
From the balanced chemical formula of Na2CO3, we know that there are 2 moles of Na for every 1 mole of Na2CO3.

Number of moles of Na = 2 * 0.499 moles
≈ 0.998 moles (rounded to three decimal places)

Step 4: Calculate the number of atoms of Na
To calculate the number of atoms, we need to use Avogadro's number, which is 6.022 x 10^23 atoms/mol.

Number of atoms of Na = 0.998 moles * 6.022 x 10^23 atoms/mol
≈ 6.009 x 10^23 atoms (rounded to three significant figures)

Answer:
There are approximately 6.009 x 10^23 atoms of Na in 53g of Na2CO3.

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