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The order of carbonyl stretching frequency in the IR spectra of ketone, amide and anhydride is:
- a)Anhydride > amide > ketone
- b)Ketone > amide > anhydride
- c)Amide > anhydride > ketone
- d)Anhydride > ketone > amide
Correct answer is option 'D'. Can you explain this answer?
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Most Upvoted Answer
The order of carbonyl stretching frequency in the IR spectra of ketone...
> Amide > Ketone
The carbonyl stretching frequency is affected by the electron density around the carbonyl group. Anhydrides have two carbonyl groups, which results in higher electron density and a higher stretching frequency. Amides have a lone pair of electrons on the nitrogen atom, which reduces the electron density on the carbonyl group and lowers the stretching frequency compared to ketones. Therefore, the order of carbonyl stretching frequency in the IR spectra of ketone, amide, and anhydride is anhydride > amide > ketone.
The carbonyl stretching frequency is affected by the electron density around the carbonyl group. Anhydrides have two carbonyl groups, which results in higher electron density and a higher stretching frequency. Amides have a lone pair of electrons on the nitrogen atom, which reduces the electron density on the carbonyl group and lowers the stretching frequency compared to ketones. Therefore, the order of carbonyl stretching frequency in the IR spectra of ketone, amide, and anhydride is anhydride > amide > ketone.
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The order of carbonyl stretching frequency in the IR spectra of ketone...
THE SIMPLE CONCEPT BEHIND THIS IS
more the EWG tendency= more the shifting of pi electron density to towards the group=more will be back bonding=less the bond order=less the IR stretching frequency of carbonyl.
more the EWG tendency= more the shifting of pi electron density to towards the group=more will be back bonding=less the bond order=less the IR stretching frequency of carbonyl.
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The order of carbonyl stretching frequency in the IR spectra of ketone, amide and anhydride is:a)Anhydride > amide > ketoneb)Ketone > amide > anhydridec)Amide > anhydride > ketoned)Anhydride > ketone > amideCorrect answer is option 'D'. Can you explain this answer?
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