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If the activation energy for the forward reaction is 150 kJ mol–1 and that of the reverse reaction is 260 kJ mol–1, what is the enthalpy change (kJ mol–1) for the reaction:
    Correct answer is '-110'. Can you explain this answer?
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    If the activation energy for the forward reaction is 150 kJ mol–...
    Delta H = Ef - Eb
    =150 - 260
    = - 110
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    If the activation energy for the forward reaction is 150 kJ mol–...
    -1, what is the activation energy for the reverse reaction?

    The activation energy for the reverse reaction cannot be determined solely from the information given. The activation energy for the reverse reaction may be different or it may be the same as the activation energy for the forward reaction. Additional information or assumptions would be needed to calculate or estimate the activation energy for the reverse reaction.
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    If the activation energy for the forward reaction is 150 kJ mol–...
    150 - 260
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    If the activation energy for the forward reaction is 150 kJ mol–1 and that of the reverse reaction is 260 kJ mol–1, what is the enthalpy change (kJ mol–1) for the reaction:Correct answer is '-110'. Can you explain this answer?
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    If the activation energy for the forward reaction is 150 kJ mol–1 and that of the reverse reaction is 260 kJ mol–1, what is the enthalpy change (kJ mol–1) for the reaction:Correct answer is '-110'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about If the activation energy for the forward reaction is 150 kJ mol–1 and that of the reverse reaction is 260 kJ mol–1, what is the enthalpy change (kJ mol–1) for the reaction:Correct answer is '-110'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for If the activation energy for the forward reaction is 150 kJ mol–1 and that of the reverse reaction is 260 kJ mol–1, what is the enthalpy change (kJ mol–1) for the reaction:Correct answer is '-110'. Can you explain this answer?.
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