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A cube-shaped permanent magnet is made of a ferromagnetic material with a magnetization M of about The side length is 2 cm. Magnetic dipole moment of the magnet is.
- a)5Am2
- b)3Am2
- c)4Am2
- d)6Am2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A cube-shaped permanent magnet is made of a ferromagnetic material wit...
Correct Answer :- C
Explanation : Magnetic Moment = Magnetization × Volume
Side of cube = 20 cm
= 0.2 m
= 500 × 0.2 × 0.2 × 0.2
= 4Am2
Most Upvoted Answer
A cube-shaped permanent magnet is made of a ferromagnetic material wit...
Correct Answer :- C
Explanation : Magnetic Moment = Magnetization × Volume
Side of cube = 20 cm
= 0.2 m
= 500 × 0.2 × 0.2 × 0.2
= 4Am2
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A cube-shaped permanent magnet is made of a ferromagnetic material wit...
Magnetic dipole moment (M) is a measure of the strength of a magnet. It is defined as the product of the magnetization (M) and the volume (V) of the magnet. In this case, we have a cube-shaped permanent magnet with a side length of 2 cm.
To calculate the magnetic dipole moment, we can use the formula:
Magnetic dipole moment (M) = Magnetization (M) * Volume (V)
Let's calculate each component separately:
1. Magnetization (M):
The question states that the magnetization (M) is about 4 A/m. This value represents the strength of magnetization of the material.
2. Volume (V):
Since the magnet is cube-shaped, the volume can be calculated using the formula for the volume of a cube:
Volume (V) = side length * side length * side length
In this case, the side length is given as 2 cm. Converting it to meters, we get:
Side length = 2 cm * (1 m / 100 cm) = 0.02 m
Using this value, we can calculate the volume:
Volume (V) = 0.02 m * 0.02 m * 0.02 m = 0.000008 m³
Now, let's substitute the values into the formula for magnetic dipole moment:
Magnetic dipole moment (M) = 4 A/m * 0.000008 m³ = 0.000032 Am²
Therefore, the magnetic dipole moment of the magnet is 0.000032 Am².
The correct answer is option 'C' (0.000032 Am²).
To calculate the magnetic dipole moment, we can use the formula:
Magnetic dipole moment (M) = Magnetization (M) * Volume (V)
Let's calculate each component separately:
1. Magnetization (M):
The question states that the magnetization (M) is about 4 A/m. This value represents the strength of magnetization of the material.
2. Volume (V):
Since the magnet is cube-shaped, the volume can be calculated using the formula for the volume of a cube:
Volume (V) = side length * side length * side length
In this case, the side length is given as 2 cm. Converting it to meters, we get:
Side length = 2 cm * (1 m / 100 cm) = 0.02 m
Using this value, we can calculate the volume:
Volume (V) = 0.02 m * 0.02 m * 0.02 m = 0.000008 m³
Now, let's substitute the values into the formula for magnetic dipole moment:
Magnetic dipole moment (M) = 4 A/m * 0.000008 m³ = 0.000032 Am²
Therefore, the magnetic dipole moment of the magnet is 0.000032 Am².
The correct answer is option 'C' (0.000032 Am²).
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