The largest equilateral triangle that can be inscribed inside a circle...
Let O be the centre of the circle . So OA=OB=OC=1cm.
To find : The side of the triangle .
Construction : Draw OD being the perpendicular bisector of side BC.
Proof : We know the angle ODB would be equal to 90degree by construction.
Now , angle B = 60degree {given}
angle OBD=30degree {half of 60degree as BO
bisects angle B}
In triangle OBD,
cos30degree= BD/OB
BD=√3/2{As OB=1}
BC=2BD=√3=1.732cm
Hence,AB=BC=CA=1.732cm. (Proved)
The largest equilateral triangle that can be inscribed inside a circle...
The Concept of Inscribed Equilateral Triangle
When dealing with circles and inscribed shapes, the largest equilateral triangle that can fit inside a circle (circumcircle) has its vertices on the circle.
Understanding the Circle and Triangle Relationship
- A circle of radius 1 cm has a diameter of 2 cm.
- The circumradius (R) of the inscribed equilateral triangle is equal to the radius of the circle.
Calculating the Side Length
For an equilateral triangle inscribed in a circle, the relationship between the side length (s) and the circumradius (R) is given by the formula:
s = R × √3
- Here, R = 1 cm (the radius of the circle).
- Substitute R into the formula:
s = 1 × √3
- This simplifies to:
s = √3
Numerical Value of the Side Length
- The numerical value of √3 is approximately 1.732.
- Therefore, the side length of the largest equilateral triangle that can be inscribed inside a circle of radius 1 cm is 1.732 cm.
Conclusion
In conclusion, the largest equilateral triangle inscribed in a circle of radius 1 cm has a side length of approximately 1.732 cm. This relationship highlights the geometric properties of triangles and circles, demonstrating the elegance of mathematical relationships in geometry.