All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
Class 12 Exam  >  Class 12 Questions  >  ReactionPrimary amine + CHCl3 + KOH → pr... Start Learning for Free
SaveJoin the Discussion on the App
Reaction
Primary amine + CHCl3 + KOH → product, here product will be -         [AIEEE-2002]
  • a)
    Cyanide
  • b)
    Isocyanide
  • c)
    Amine
  • d)
    Alcohol
Correct answer is option 'B'. Can you explain this answer?
FREE This question is part of
Download PDF Attempt Test
Download PDF Attempt this Test
Verified Answer
ReactionPrimary amine + CHCl3 + KOH → product, here product will ...
The correct answer is Option B.
When primary amine reacts with CHCl3 in alcoholic KOH, the product is isocyanide which is foul smelling.
R−NH2+CHCl3+3KOH -ΔR−NC+3KCl+3H2O
This reaction is known as carbylamine test / Isocyande test. This test is not given by secondary or tertiary amines.
View all questions of this test
Most Upvoted Answer
ReactionPrimary amine + CHCl3 + KOH → product, here product will ...
The correct answer is Option B.
When primary amine reacts with CHCl3 in alcoholic KOH, the product is isocyanide which is foul smelling.
R−NH2+CHCl3+3KOH -ΔR−NC+3KCl+3H2O
This reaction is known as carbylamine test / Isocyande test. This test is not given by secondary or tertiary amines.
Free Test
FREE
Start Free Test
Start Free Test
Community Answer
ReactionPrimary amine + CHCl3 + KOH → product, here product will ...
The correct answer is Option B.
When primary amine reacts with CHCl3 in alcoholic KOH, the product is isocyanide which is foul smelling.
R−NH2+CHCl3+3KOH -ΔR−NC+3KCl+3H2O
This reaction is known as carbylamine test / Isocyande test. This test is not given by secondary or tertiary amines.
< Previous Question Next Question >
Explore Courses for Class 12 exam

Similar Class 12 Doubts

Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer?
Question Description
ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer?.
Solutions for ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12. Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 12 tests.
Explore Courses for Class 12 exam
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Follow Us
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup