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Reaction
Primary amine + CHCl3 + KOH → product, here product will be -         [AIEEE-2002]
  • a)
    Cyanide
  • b)
    Isocyanide
  • c)
    Amine
  • d)
    Alcohol
Correct answer is option 'B'. Can you explain this answer?
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Verified Answer
ReactionPrimary amine + CHCl3 + KOH → product, here product will ...
The correct answer is Option B.
When primary amine reacts with CHCl3 in alcoholic KOH, the product is isocyanide which is foul smelling.
R−NH2+CHCl3+3KOH -ΔR−NC+3KCl+3H2O
This reaction is known as carbylamine test / Isocyande test. This test is not given by secondary or tertiary amines.
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Most Upvoted Answer
ReactionPrimary amine + CHCl3 + KOH → product, here product will ...
The correct answer is Option B.
When primary amine reacts with CHCl3 in alcoholic KOH, the product is isocyanide which is foul smelling.
R−NH2+CHCl3+3KOH -ΔR−NC+3KCl+3H2O
This reaction is known as carbylamine test / Isocyande test. This test is not given by secondary or tertiary amines.
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Community Answer
ReactionPrimary amine + CHCl3 + KOH → product, here product will ...
The correct answer is Option B.
When primary amine reacts with CHCl3 in alcoholic KOH, the product is isocyanide which is foul smelling.
R−NH2+CHCl3+3KOH -ΔR−NC+3KCl+3H2O
This reaction is known as carbylamine test / Isocyande test. This test is not given by secondary or tertiary amines.
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Read the passage given below and answer the following questions:Reductive alkylation is the term applied to the process of introducing alkyl groups into ammonia or a primary or secondary amine by means of an aldehyde or ketone in the presence of a reducing agent. The present discussion is limited to those reductive alkylations in which the reducing agent is hydrogen and a catalyst or "nascent" hydrogen, usually from a metalacid combination; most of these reductive alkylations have been carried out with hydrogen and a catalyst. The principal variation excluded is that in which the reducing agent is formic acid or one of its derivatives; this modification is known as the Leuckart reaction. The process of reductive alkylation of ammonia consists in the addition of ammonia to a carbonyl compound and reduction of the addition compound or its dehydration product. The reaction usually is carried out in ethanol solution when the reduction is to be effected catalytically:Since the primary amine is formed in the presence of the aldehyde it may react in the same way as ammonia, yielding an additional compound, a Schiff's base (RCH= NCH2R) and finally, a secondary amine. Similarly, the primary amine may react with the imine, forming an addition product which also is reduced to a secondary amine Finally, the secondary amine may react with either the aldehyde or the imine to give products which are reduced to tertiary amines.Similar reactions may occur when the carbonyl compound employed is a ketone.Q. The reaction of ammonia and its derivatives with aldehydes is called

ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer?
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ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for ReactionPrimary amine + CHCl3 + KOH → product, here product will be - [AIEEE-2002]a)Cyanideb)Isocyanidec)Amined)AlcoholCorrect answer is option 'B'. Can you explain this answer?.
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