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A reaction of first-order completed 90% in 90 minutes, hence, it is completed 50% in approximately.
  • a)
    50 min
  • b)
    54 min
  • c)
    27 min
  • d)
    62 min
Correct answer is option 'C'. Can you explain this answer?
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Given:
- A first-order reaction is completed 90% in 90 minutes.
- We need to find the time taken for the reaction to complete 50%.

We can use the formula for first-order reactions to solve this problem:

ln(Nt/N0) = -kt

where,
- Nt is the concentration at time t
- N0 is the initial concentration
- k is the rate constant
- t is the time

To find the time taken for the reaction to complete 50%, we need to find the time at which Nt/N0 = 0.5.

ln(0.5) = -k(t)

Solving for t, we get:

t = ln(0.5)/(-k)

We know that the reaction is completed 90% in 90 minutes, which means that Nt/N0 = 0.1 when t = 90.

ln(0.1) = -k(90)

Solving for k, we get:

k = ln(0.1)/(-90)

Substituting the value of k in the equation for t, we get:

t = ln(0.5)/(-ln(0.1)/90)

t = 27.03 minutes

Therefore, the time taken for the reaction to complete 50% is approximately 27 minutes (option C).
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A reaction of first-order completed 90% in 90 minutes, hence, it is completed 50% in approximately.a)50 minb)54 minc)27 mind)62 minCorrect answer is option 'C'. Can you explain this answer?
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