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The terminal velocity of a steel ball of 4 mm in diameter falling through a glycerin of viscosity 3.3 poise, given relative density of steel is 8, relative density of glycerin is 1.3 is
  • a)
    13.23 cm s-1
  • b)
    17.47 cm s-1
  • c)
    1.47 cm s-1
  • d)
    1.77 cm s-1
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The terminal velocity of a steel ball of 4 mm in diameter falling thro...
Given:
Diameter of steel ball, d = 4 mm
Relative density of steel, ρs = 8
Relative density of glycerin, ρg = 1.3
Viscosity of glycerin, η = 3.3 poise

To find: Terminal velocity of the steel ball falling through glycerin

Terminal Velocity
Terminal velocity is the maximum velocity achieved by a freely falling object when the resistance of the medium through which it is falling prevents further acceleration.

Stokes' Law
Stokes' law gives the terminal velocity of a small spherical object falling through a viscous fluid. It is given by:

v = (2/9) * [(ρs - ρg) * g * d^2] / η

where,
v = Terminal velocity
ρs = Density of the steel ball
ρg = Density of the glycerin
g = Acceleration due to gravity
d = Diameter of the steel ball
η = Viscosity of the glycerin

Substituting the given values in the above equation, we get:

v = (2/9) * [(8 - 1.3) * 9.8 * (4/1000)^2] / 3.3

v = 0.1747 m/s
v = 17.47 cm/s

Therefore, the terminal velocity of the steel ball falling through glycerin is 17.47 cm/s. Hence, option (b) is the correct answer.
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Community Answer
The terminal velocity of a steel ball of 4 mm in diameter falling thro...
= 17.47 cm /s is correct answer
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Attempt All sub parts from each question.Newtonian and non-Newtonian fluid: Viscosity is the physical property that characterizes the flow resistance of simple fluids. Newton’s law of viscosity defines the relationship between the shear stress and shear rate of a fluid subjected to a mechanical stress. The ratio of shear stress to shear rate is a constant, for a given temperature and pressure, and is defined as the viscosity or coefficient of viscosity. Newtonian fluids obey Newton’s law of viscosity. The viscosity is independent of the shear rate. Example: air, water, alcohol etc. Non-Newtonian fluids do not follow Newton’s law thus, their viscosity (ratio of shear stress to shear rat e) is not constant and is dependent on the shear rate. Example: honey, ketchup etc. Non-Newtonian fluids can be categorized into four types based on the way a fluid’s viscosity changes in response to variations in shear rate.• Pseudoplastic: Materials whose viscosity decreases as the shear rate increases. This type of flow behavior is sometimes called shear thinning. Example: Cake batter, agar-agar and fruit juice concentrates, nail polish etc.• Dilatant: M aterials whose viscosity increases as the shear rate increases. This type of behavior is sometimes called shear-thickening. Example: Suspension of corn starch in water and candy compounds etc..• Thixotropic: M aterials whose viscosity decreases when sheared at a constant rate over time. Example: Yogurt, gelatin gel, honey etc.• Rheopectic: M aterials whose viscosity increases when sheared at a constant rate over time. Example: Printer ink, gypsum paste etc.Q. Newton’s law of viscosity states

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The terminal velocity of a steel ball of 4 mm in diameter falling through a glycerin of viscosity 3.3 poise, given relative density of steel is 8, relative density of glycerin is 1.3 isa)13.23 cm s-1b)17.47 cm s-1c)1.47 cm s-1​d)1.77 cm s-1Correct answer is option 'B'. Can you explain this answer?
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The terminal velocity of a steel ball of 4 mm in diameter falling through a glycerin of viscosity 3.3 poise, given relative density of steel is 8, relative density of glycerin is 1.3 isa)13.23 cm s-1b)17.47 cm s-1c)1.47 cm s-1​d)1.77 cm s-1Correct answer is option 'B'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The terminal velocity of a steel ball of 4 mm in diameter falling through a glycerin of viscosity 3.3 poise, given relative density of steel is 8, relative density of glycerin is 1.3 isa)13.23 cm s-1b)17.47 cm s-1c)1.47 cm s-1​d)1.77 cm s-1Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The terminal velocity of a steel ball of 4 mm in diameter falling through a glycerin of viscosity 3.3 poise, given relative density of steel is 8, relative density of glycerin is 1.3 isa)13.23 cm s-1b)17.47 cm s-1c)1.47 cm s-1​d)1.77 cm s-1Correct answer is option 'B'. Can you explain this answer?.
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