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The excess pressure inside an air bubble is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
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I know the expression for excess pressure inside a LIQUID DROP is :
P2−P1=2S/RP2−P1=2S/R
where P2P2 is the pressure just inside the liquid dropand P1P1 is the pressure outside the liquid drop and SSis surface tension of water.
I considered equilibrium of one hemisphere of the liquid drop and balanced the forces which gave me the above result.
However, upon reading some illustrations I observed that the pressure inside an AIR BUBBLE in a tank of water is also

P2−P1=2S/R(1)(1)P2−P1=2S/R
where P2P2 is the pressure just inside the air nd P1P1 is the pressure outside the air bubble and SSis surface tension of water.
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The excess pressure inside an air bubble isa)b)c)d)Correct answer is option 'C'. Can you explain this answer?
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