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A suitcase is gently dropped on a conveyor belt movingat 3 ms-1. If the coefficient of friction between the beltand the suitcase is 0.5, find the displacement of thesuitcase relative to conveyor belt before the slippingbetween the two is stopped : (g = 10 ms-2).
  • a)
    2.7 m
  • b)
    1.8 m
  • c)
    0.9 m
  • d)
    1.2 m
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A suitcase is gently dropped on a conveyor belt movingat 3 ms-1. If th...
Given, initial velocity of the conveyor belt, u = 0, final velocity of the conveyor belt, v = 3 m/s, coefficient of friction, μ = 0.5 and acceleration due to gravity, g = 10 m/s².

Let's assume the displacement of the suitcase relative to the conveyor belt before slipping is stopped be d.

From the equation of motion, v² = u² + 2as,

where s is the displacement of the suitcase relative to the conveyor belt before slipping is stopped.

We can rewrite the equation as s = (v² - u²)/2a.

Here, acceleration, a = μg. Substituting the given values, we get:

s = (3² - 0²)/2×0.5×10

s = 9/10

s = 0.9 m

Therefore, the displacement of the suitcase relative to the conveyor belt before slipping is stopped is 0.9 m.

Hence, option C is the correct answer.
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A suitcase is gently dropped on a conveyor belt movingat 3 ms-1. If th...
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A suitcase is gently dropped on a conveyor belt movingat 3 ms-1. If the coefficient of friction between the beltand the suitcase is 0.5, find the displacement of thesuitcase relative to conveyor belt before the slippingbetween the two is stopped : (g = 10 ms-2).a)2.7 mb)1.8 mc)0.9 md)1.2 mCorrect answer is option 'C'. Can you explain this answer?
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