Class 11 Exam > Class 11 Questions > A solid shell losses half of its weight in wa...
Start Learning for Free
A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow?
Most Upvoted Answer
A solid shell losses half of its weight in water , relative density of...
Calculating the Fraction of Hollow Volume in a Solid Shell
To determine the fraction of hollow volume in a solid shell, we need to consider its weight loss in water and its relative density.
Weight Loss in Water
When a solid object is immersed in a fluid, it experiences an upward buoyant force equal to the weight of the fluid it displaces. In this case, the solid shell loses half of its weight in water. This means that the buoyant force acting on the shell when submerged in water is equal to half of its weight.
Relative Density
The relative density of a substance is the ratio of its density to the density of a reference substance. In this case, the relative density of the shell is given as 5. This means that the density of the shell is 5 times greater than the density of the reference substance, which is typically water.
Fraction of Hollow Volume
To calculate the fraction of hollow volume in the solid shell, we can use the concept of relative density.
1. Let's assume the original weight of the solid shell is W, and the weight loss in water is W/2.
2. Since the buoyant force acting on the shell is equal to half its weight, the buoyant force is W/2.
3. The buoyant force acting on the shell is also equal to the weight of the water displaced by the shell.
4. The volume of water displaced by the shell is given by the equation V_water = (W/2) / ρ_water, where ρ_water is the density of water.
5. The volume of the shell is given by V_shell = W / ρ_shell, where ρ_shell is the density of the shell.
6. The fraction of hollow volume in the shell can be calculated as the difference between the volume of the shell and the volume of water displaced, divided by the volume of the shell: (V_shell - V_water) / V_shell.
Explanation
The fraction of hollow volume in the solid shell can be calculated by subtracting the volume of water displaced by the shell from the volume of the shell, and then dividing the result by the volume of the shell. This fraction represents the portion of the shell's volume that is hollow.
By considering the weight loss in water and the relative density of the shell, we can determine the fraction of hollow volume in the shell.
To determine the fraction of hollow volume in a solid shell, we need to consider its weight loss in water and its relative density.
Weight Loss in Water
When a solid object is immersed in a fluid, it experiences an upward buoyant force equal to the weight of the fluid it displaces. In this case, the solid shell loses half of its weight in water. This means that the buoyant force acting on the shell when submerged in water is equal to half of its weight.
Relative Density
The relative density of a substance is the ratio of its density to the density of a reference substance. In this case, the relative density of the shell is given as 5. This means that the density of the shell is 5 times greater than the density of the reference substance, which is typically water.
Fraction of Hollow Volume
To calculate the fraction of hollow volume in the solid shell, we can use the concept of relative density.
1. Let's assume the original weight of the solid shell is W, and the weight loss in water is W/2.
2. Since the buoyant force acting on the shell is equal to half its weight, the buoyant force is W/2.
3. The buoyant force acting on the shell is also equal to the weight of the water displaced by the shell.
4. The volume of water displaced by the shell is given by the equation V_water = (W/2) / ρ_water, where ρ_water is the density of water.
5. The volume of the shell is given by V_shell = W / ρ_shell, where ρ_shell is the density of the shell.
6. The fraction of hollow volume in the shell can be calculated as the difference between the volume of the shell and the volume of water displaced, divided by the volume of the shell: (V_shell - V_water) / V_shell.
Explanation
The fraction of hollow volume in the solid shell can be calculated by subtracting the volume of water displaced by the shell from the volume of the shell, and then dividing the result by the volume of the shell. This fraction represents the portion of the shell's volume that is hollow.
By considering the weight loss in water and the relative density of the shell, we can determine the fraction of hollow volume in the shell.
Community Answer
A solid shell losses half of its weight in water , relative density of...
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow?
Question Description
A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow?.
A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow?.
Solutions for A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? defined & explained in the simplest way possible. Besides giving the explanation of
A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow?, a detailed solution for A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? has been provided alongside types of A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? theory, EduRev gives you an
ample number of questions to practice A solid shell losses half of its weight in water , relative density of shell is 5. What fraction of its volume is hollow? tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup