A path 4m wide runs around the inside of a square park of side 100m.fi...
See the attached figure :-
given ,
length of the big square = 100 m
length of the small square = 5 m
Side of the smaller square = Side of the bigger square - 2(width of the path)
= 100 - 2(5)
= 90 m
Area of the path = (100)^2- (90)^2 = 10000 - 8100 = 1900 sq m
Cost of cementing at the rate of Rs 250 per 10 m2 = 250 x 190 = Rs 47500
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A path 4m wide runs around the inside of a square park of side 100m.fi...
Area of the Path:
To find the area of the path, we need to subtract the area of the inner square from the area of the outer square. The width of the path is given as 4m.
Step 1: Find the area of the inner square:
The side length of the inner square is 100m, so the area can be calculated using the formula A = s^2, where A is the area and s is the side length of the square.
A_inner = 100m * 100m = 10,000m^2
Step 2: Find the area of the outer square:
The side length of the outer square is the sum of the side length of the inner square and twice the width of the path.
Side length of outer square = 100m + 2 * 4m = 100m + 8m = 108m
A_outer = 108m * 108m = 11,664m^2
Step 3: Calculate the area of the path:
The area of the path is the difference between the area of the outer square and the area of the inner square.
A_path = A_outer - A_inner = 11,664m^2 - 10,000m^2 = 1,664m^2
Therefore, the area of the path is 1,664 square meters.
Cost of Leveling the Path:
To calculate the cost of leveling the path, we need to multiply the area of the path by the cost per square meter, which is given as rupees 5.
Cost = Area * Cost per square meter
Cost = 1,664m^2 * 5 rupees/m^2 = 8,320 rupees
Therefore, the cost of leveling the path at rupees 5 per square meter is 8,320 rupees.
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