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The Viral equation for ethane gas is given by PV=RT BP. At zero degree Celsius, B=-0.1814 L/mol. Calculate volume of one mole of ethane at 10 atm, and 'a' .?
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The Viral equation for ethane gas is given by PV=RT BP. At zero degree...
The Viral Equation for Ethane Gas

The Viral equation is used to describe the behavior of gases under various conditions, taking into account factors such as pressure, volume, temperature, and the characteristics of the gas itself. In the case of ethane gas, the Viral equation is given by PV = RT + BP, where P represents the pressure, V is the volume, R is the gas constant, T denotes the temperature, and BP is the correction term for the intermolecular forces.

Given Information

- Temperature (T) = 0 degrees Celsius (273.15 K)
- B = -0.1814 L/mol

Calculating the Volume of One Mole of Ethane at 10 atm

To calculate the volume of one mole of ethane at a pressure of 10 atm, we can rearrange the Viral equation as follows:

PV = RT + BP

Since we want to find the volume (V), we can rearrange the equation further:

V = (RT + BP) / P

Substituting the given values, we have:

V = (R * 273.15 K + (-0.1814 L/mol)) / 10 atm

The gas constant R has a value of 0.0821 L·atm/(mol·K). Plugging in this value, we get:

V = (0.0821 L·atm/(mol·K) * 273.15 K + (-0.1814 L/mol)) / 10 atm

Simplifying the equation, we have:

V = (22.414 + (-0.1814)) / 10 L/mol

V = 22.2326 / 10 L/mol

V = 2.22326 L/mol

Therefore, the volume of one mole of ethane gas at 10 atm is approximately 2.22326 liters per mole.

Calculating the 'a' Value

In the Viral equation, the 'a' term represents the correction factor for the volume of the gas molecules themselves. It takes into account the size of the molecules and any attractive forces between them. Unfortunately, the 'a' value for ethane gas was not provided in the given information. This value can vary depending on the specific gas being considered.

To calculate the 'a' value for ethane gas, it would be necessary to have additional information such as experimental data or a known reference value. Without this information, it is not possible to determine the 'a' value accurately.

Therefore, the 'a' value for ethane gas cannot be calculated with the given information.

Summary

- The Viral equation PV = RT + BP is used to describe the behavior of gases.
- To calculate the volume of one mole of ethane gas at a given pressure, the Viral equation can be rearranged.
- Using the given values, the volume of one mole of ethane gas at 10 atm was calculated to be approximately 2.22326 liters per mole.
- The 'a' value, which represents the correction factor for molecular size and attractive forces, cannot be calculated without additional information.
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The Viral equation for ethane gas is given by PV=RT BP. At zero degree Celsius, B=-0.1814 L/mol. Calculate volume of one mole of ethane at 10 atm, and 'a' .?
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The Viral equation for ethane gas is given by PV=RT BP. At zero degree Celsius, B=-0.1814 L/mol. Calculate volume of one mole of ethane at 10 atm, and 'a' .? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about The Viral equation for ethane gas is given by PV=RT BP. At zero degree Celsius, B=-0.1814 L/mol. Calculate volume of one mole of ethane at 10 atm, and 'a' .? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The Viral equation for ethane gas is given by PV=RT BP. At zero degree Celsius, B=-0.1814 L/mol. Calculate volume of one mole of ethane at 10 atm, and 'a' .?.
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