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Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice?
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Ice at 0 degree celcuis is added to 200g of water initially at 70 degr...
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Ice at 0 degree celcuis is added to 200g of water initially at 70 degr...
Given data:
Initial temperature of water = 70°C
Mass of water = 200g
Mass of ice added = 50g, 80g
Final temperature of water and ice mixture after adding 50g of ice = 40°C
Final temperature of water and ice mixture after adding 80g of ice = 10°C
Calculating the heat gained by the water:
The heat gained by the water can be calculated using the equation:
Q = mcΔT
Where:
Q = heat gained by the water
m = mass of water
c = specific heat capacity of water
ΔT = change in temperature
The specific heat capacity of water is 4.18 J/g°C.
Calculation for when 50g of ice has melted:
The initial temperature of the water is 70°C and the final temperature is 40°C. Therefore, the change in temperature (ΔT) is:
ΔT = final temperature - initial temperature
ΔT = 40°C - 70°C
ΔT = -30°C
The heat gained by the water is:
Q = mcΔT
Q = (200g)(4.18 J/g°C)(-30°C)
Q = -25080 J
Calculating the heat gained by the ice:
The heat gained by the ice can be calculated using the equation:
Q = mL
Where:
Q = heat gained by the ice
m = mass of ice
L = specific latent heat of fusion of ice
Calculation for when 50g of ice has melted:
The heat gained by the ice is equal to the heat lost by the water, since the system is isolated. Therefore:
Q = -25080 J
Using the equation Q = mL, we can solve for the specific latent heat of fusion of ice (L):
-25080 J = (50g)(L)
L = -25080 J / 50g
L = -501.6 J/g
The negative sign indicates that heat is being released by the system.
Calculation for when 80g of ice has melted:
The initial temperature of the water and ice mixture is 40°C and the final temperature is 10°C. Therefore, the change in temperature (ΔT) is:
ΔT = final temperature - initial temperature
ΔT = 10°C - 40°C
ΔT = -30°C
The heat gained by the water is:
Q = mcΔT
Q = (200g)(4.18 J/g°C)(-30°C)
Q = -25080 J
The heat gained by the ice is equal to the heat lost by the water, since the system is isolated. Therefore:
Q = -25080 J
Using the equation Q = mL, we can solve for the specific latent heat of fusion of ice (L):
-25080 J = (80g)(L)
L = -25080 J / 80g
L = -313.5 J/g
Again, the negative sign indicates that heat is being released by the system.
Conclusion:
The specific latent heat of fusion of ice can be calculated to be approximately -501.6 J/g when 50g of ice is melted, and approximately -313.
Initial temperature of water = 70°C
Mass of water = 200g
Mass of ice added = 50g, 80g
Final temperature of water and ice mixture after adding 50g of ice = 40°C
Final temperature of water and ice mixture after adding 80g of ice = 10°C
Calculating the heat gained by the water:
The heat gained by the water can be calculated using the equation:
Q = mcΔT
Where:
Q = heat gained by the water
m = mass of water
c = specific heat capacity of water
ΔT = change in temperature
The specific heat capacity of water is 4.18 J/g°C.
Calculation for when 50g of ice has melted:
The initial temperature of the water is 70°C and the final temperature is 40°C. Therefore, the change in temperature (ΔT) is:
ΔT = final temperature - initial temperature
ΔT = 40°C - 70°C
ΔT = -30°C
The heat gained by the water is:
Q = mcΔT
Q = (200g)(4.18 J/g°C)(-30°C)
Q = -25080 J
Calculating the heat gained by the ice:
The heat gained by the ice can be calculated using the equation:
Q = mL
Where:
Q = heat gained by the ice
m = mass of ice
L = specific latent heat of fusion of ice
Calculation for when 50g of ice has melted:
The heat gained by the ice is equal to the heat lost by the water, since the system is isolated. Therefore:
Q = -25080 J
Using the equation Q = mL, we can solve for the specific latent heat of fusion of ice (L):
-25080 J = (50g)(L)
L = -25080 J / 50g
L = -501.6 J/g
The negative sign indicates that heat is being released by the system.
Calculation for when 80g of ice has melted:
The initial temperature of the water and ice mixture is 40°C and the final temperature is 10°C. Therefore, the change in temperature (ΔT) is:
ΔT = final temperature - initial temperature
ΔT = 10°C - 40°C
ΔT = -30°C
The heat gained by the water is:
Q = mcΔT
Q = (200g)(4.18 J/g°C)(-30°C)
Q = -25080 J
The heat gained by the ice is equal to the heat lost by the water, since the system is isolated. Therefore:
Q = -25080 J
Using the equation Q = mL, we can solve for the specific latent heat of fusion of ice (L):
-25080 J = (80g)(L)
L = -25080 J / 80g
L = -313.5 J/g
Again, the negative sign indicates that heat is being released by the system.
Conclusion:
The specific latent heat of fusion of ice can be calculated to be approximately -501.6 J/g when 50g of ice is melted, and approximately -313.
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Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice?
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Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice?.
Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice?.
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Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice?, a detailed solution for Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice? has been provided alongside types of Ice at 0 degree celcuis is added to 200g of water initially at 70 degree celcuis in a vacuum flask.When 50g of ice has been added and has all melted the temperature of the flask and contents is 40 degree Celsius when a further 80gm of ice has been added and has all melted the temperature of the whole is 10 degree Celsius calculate the specific latent heat of fusion of ice? theory, EduRev gives you an
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