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Steam at 100 degree Celsius is passed into 20 gram of water at 10 degree Celsius. When water aquires a temperature of 80 degree Celsius, the mass of water present will be?(specific heat of water =1;latent heat of steam =540) ?
Verified Answer
Steam at 100 degree Celsius is passed into 20 gram of water at 10 degr...
Heat lost by the steam = heat gained by water
Let, m' be the amount of heat converted into water
m' x L = ms 
m' x 540 = 20 x 1 x (80 - 10)
m' = 
Therefore, net amount of water = 20 + 2.5 = 22.5 g
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Steam at 100 degree Celsius is passed into 20 gram of water at 10 degree Celsius. When water aquires a temperature of 80 degree Celsius, the mass of water present will be?(specific heat of water =1;latent heat of steam =540) ?
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Steam at 100 degree Celsius is passed into 20 gram of water at 10 degree Celsius. When water aquires a temperature of 80 degree Celsius, the mass of water present will be?(specific heat of water =1;latent heat of steam =540) ? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Steam at 100 degree Celsius is passed into 20 gram of water at 10 degree Celsius. When water aquires a temperature of 80 degree Celsius, the mass of water present will be?(specific heat of water =1;latent heat of steam =540) ? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Steam at 100 degree Celsius is passed into 20 gram of water at 10 degree Celsius. When water aquires a temperature of 80 degree Celsius, the mass of water present will be?(specific heat of water =1;latent heat of steam =540) ?.
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