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A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is?
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A person holds a bucket of weight 60n he walks 7m along a horizontal p...
Calculation of Work Done by the Person
To calculate the work done by the person, we need to know the formula for work. The formula for work is:
Work = Force x Distance x Cosine (theta)
Where,
Force = 60 N (weight of the bucket)
Distance = 7 m (horizontal distance covered)
Cosine (theta) = Cosine of the angle between the force and the direction of motion (theta is 0 degrees for horizontal motion and 90 degrees for vertical motion)
Work Done in the Horizontal Path
In the horizontal path, the person moves the bucket for a distance of 7 meters. As the angle between the force and the direction of motion is 0 degrees, the cosine of theta is 1. Therefore, the work done in the horizontal path is:
Work = Force x Distance x Cosine (theta)
= 60 N x 7 m x 1
= 420 Joules
Work Done in the Vertical Path
In the vertical path, the person moves the bucket for a vertical distance of 5 meters. As the angle between the force and the direction of motion is 90 degrees, the cosine of theta is 0. Therefore, the work done in the vertical path is:
Work = Force x Distance x Cosine (theta)
= 60 N x 5 m x 0
= 0 Joules
Total Work Done by the Person
To calculate the total work done by the person, we need to add the work done in the horizontal path and the work done in the vertical path. Therefore, the total work done by the person is:
Total Work = Work Done in the Horizontal Path + Work Done in the Vertical Path
= 420 Joules + 0 Joules
= 420 Joules
Therefore, the work done by the person is 420 Joules.
To calculate the work done by the person, we need to know the formula for work. The formula for work is:
Work = Force x Distance x Cosine (theta)
Where,
Force = 60 N (weight of the bucket)
Distance = 7 m (horizontal distance covered)
Cosine (theta) = Cosine of the angle between the force and the direction of motion (theta is 0 degrees for horizontal motion and 90 degrees for vertical motion)
Work Done in the Horizontal Path
In the horizontal path, the person moves the bucket for a distance of 7 meters. As the angle between the force and the direction of motion is 0 degrees, the cosine of theta is 1. Therefore, the work done in the horizontal path is:
Work = Force x Distance x Cosine (theta)
= 60 N x 7 m x 1
= 420 Joules
Work Done in the Vertical Path
In the vertical path, the person moves the bucket for a vertical distance of 5 meters. As the angle between the force and the direction of motion is 90 degrees, the cosine of theta is 0. Therefore, the work done in the vertical path is:
Work = Force x Distance x Cosine (theta)
= 60 N x 5 m x 0
= 0 Joules
Total Work Done by the Person
To calculate the total work done by the person, we need to add the work done in the horizontal path and the work done in the vertical path. Therefore, the total work done by the person is:
Total Work = Work Done in the Horizontal Path + Work Done in the Vertical Path
= 420 Joules + 0 Joules
= 420 Joules
Therefore, the work done by the person is 420 Joules.
Community Answer
A person holds a bucket of weight 60n he walks 7m along a horizontal p...
WD= 60 × 5 = 300 J
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A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is?
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A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is?.
A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A person holds a bucket of weight 60n he walks 7m along a horizontal path and then stairs-up a vertical distance of 5m.tbe work done by the person is?.
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